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The main purpose of templates is to provide a generic definition of classes and functions that may then be tailored to specific types.
But templates allow us to do more than that. If not for compiler implementation limitations, templates could be used to program, at compile-time, just about anything we use computers for. This remarkable feat, offered by no other current-day computer language, stems from the fact that templates allow us to do three things at compile-time:
Of course, asking the compiler to compute, e.g., prime numbers, is one thing. But it's a completely different thing to do so in an award winning way. Don't expect speed records to be broken when the compiler performs complex calculations for us. But that's all beside the point. In the end we can ask the compiler to compute virtually anything using C++'s template language, including prime numbers....
In this chapter these remarkable features of templates are discussed. Following a short overview of subtleties related to templates the main characteristics of template meta programming are introduced.
In addition to template type and template non-type parameters there is a third kind of template parameter, the template template parameter. This kind of template parameter is introduced next, laying the groundwork for the discusion of trait classes and policy classes.
This chapter ends with the discussion of several additional and interesting applications of templates: adapting compiler error messages, conversions to class types and an elaborate example discussing compile-time list processing.
Much of the inspiration for this chapter came from two highly recommended books: Andrei Alexandrescu's 2001 book Modern C++ design (Addison-Wesley) and Nicolai Josutis and David Vandevoorde's 2003 book Templates (Addison-Wesley).
typename
was discussed. There we learned that it is not only used to define a name for
a (complex) type, but also to distinguish types defined by class templates
from members defined by class templates. In this section two more
applications of typename
are introduced:
typename
to situations
where types nested in templates are returned from member functions of class
templates;
typename
section
23.1.3 introduces some new syntax that is related to the extended use of
the keyword typename
: ::template, .template
and ->template
are
used to inform the compiler that a name used inside a template is itself a
class template.
nested
returns an object of this nested class. The example uses a
(deprecated) in-class member implementation. The reason for this shortly
becomes clear.
template <typename T> class Outer { public: class Nested {}; Nested nested() const { return Nested(); } };The above example compiles flawlessly. Inside the class
Outer
there is
no ambiguity with respect to the meaning of nested
's return type.
However, following good practices inline and template members should be implemented below their class interfaces (see section 7.9.1). So we remove the implementation from the interface and put it below the interface:
template <typename T> class Outer { public: class Nested {}; Nested nested() const; }; template <typename T> Outer<T>::Nested Outer<T>::nested() const { return Nested(); }Suddenly the compiler refuses to compile the
nested
member, producing an
error message like
error: expected constructor, destructor, or type conversion before 'Outer'.Now that the implementation is moved out of the interface the return type (i.e.,
Outer<T>::Nested
) refers to a type defined by Outer<T>
rather
than to a member of Outer<T>
.
Here typename
must once again be used. The general rule being: the
keyword typename
must be used whenever a type is referred to that is a
subtype of a type that itself depends on a template type parameter.
When using the inline implementation no such dependency is used as the
function's return type is simply Nested
. When implementing the function
outside of the class interface (which should be considered `good practice')
then a specification of the class defining Nested
must be provided for the
function's return type. So it becomes Outer<T>::Nested
which clearly is a
type depending on a template type parameter.
Like before, writing typename
in front of Outer<T>::Nested
removes
the compilation error. Thus, the correct implementation of the function
nested
becomes:
template <typename T> typename Outer<T>::Nested Outer<T>::nested() const { return Nested(); }
Base
and Derived
, Base
being
Derived
's base class:
#include <iostream> template <typename T> class Base { public: void member(); }; template <typename T> void Base<T>::member() { std::cout << "This is Base<T>::member()\n"; } template <typename T> class Derived: public Base<T> { public: Derived(); }; template <typename T> Derived<T>::Derived() { member(); }
This example won't compile, and the compiler tells us something like:
error: there are no arguments to 'member' that depend on a template parameter, so a declaration of 'member' must be availableThis error causes some confusion as ordinary (non-template) base classes readily make their public and protected members available to classes that are derived from them. This is no different for class templates, but only if the compiler can figure out what we mean. In the above example the compiler can't as it doesn't know for what type
T
the member function
member
must be initialized when called from Derived<T>::Derived
.
To appreciate why this is true, consider the situation where we have defined a specialization:
template <> Base<int>::member() { std::cout << "This is the int-specialization\n"; }Since the compiler, when
Derived<SomeType>::Derived
is called, does
not know whether a specialization of member
is in effect, it can't
decide (when compiling Derived<T>::Derived
) for what type to instantiate
member
. It can't decide this when compiling Derived<T>::Derived
as
member
's call in Derived::Derived
doesn't require a template type
parameter.
In cases like these, where no template type parameter is available to
determine which type to use, the compiler must be told that it should postpone
its decision about the template type parameter to use (and therefore about the
particular (here: member
) function to call)
until instantiation time.
This may be implemented in two ways: either by using this
or by
explicitly mentioning the base class, instantiated for the derived class's
template type(s). When this
is used the compiler is informed that we're
referring to the type T
for which the template was instantiated. Any
confusion about which member function to use (the derived class or base class
member) is resolved in favor of the derived class member. Alternatively, the
base or derived class can explicitly be mentioned (using Base<T>
or
Derived<T>
) as shown in the next example. Note that with the int
template type the int
specialization is used.
#include <iostream> template <typename T> class Base { public: virtual void member(); }; template <typename T> void Base<T>::member() { std::cout << "This is Base<T>::member()\n"; } template <> void Base<int>::member() { std::cout << "This is the int-specialization\n"; } template <typename T> class Derived: public Base<T> { public: Derived(); virtual void member(); }; template <typename T> void Derived<T>::member() { std::cout << "This is Derived<T>::member()\n"; } template <typename T> Derived<T>::Derived() { this->member(); // Using `this' implies using the // type for which T was instantiated Derived<T>::member(); // Same: calls the Derived member Base<T>::member(); // Same: calls the Base member std::cout << "Derived<T>::Derived() completed\n"; } int main() { Derived<double> d; Derived<int> i; } /* Generated output: This is Derived<T>::member() This is Derived<T>::member() This is Base<T>::member() Derived<T>::Derived() completed This is Derived<T>::member() This is Derived<T>::member() This is the int-specialization Derived<T>::Derived() completed */
The above example also illustrates the use of virtual member templates
(although virtual member templates aren't often used). In the example Base
declares a virtual void member
and Derived
defines its overriding
function member
. In that case this->member()
in Derived::Derived
calls, due to member
's virtual nature, Derived::member
. The statement
Base<T>::member()
, however, always calls Base
's member
function
and can be used to
bypass dynamic polymorphism.
typename
keyword may often be used for that purpose.
But typename
cannot always come to the rescue. While parsing a source the
compiler receives a series of tokens, representing meaningful units of
text encountered in the program's source. A token could represent, e.g., an
identifier or a number. Other tokens represent operators, like =, +
or
<
. It is precisely the last token that may cause problems as it may have
very different meanings. The correct meaning cannot always be determined from
the context in which the compiler encounters <
. In some situations the
compiler does know that <
does not represent the less than
operator, as when a template parameter list follows the keyword template
,
e.g.,
template <typename T, int N>Clearly, in this case
<
does not represent a `less than' operator.
The special meaning of <
when it is preceded by template
forms the
basis for the syntactic constructs discussed in this section.
Assume the following class has been defined:
template <typename Type> class Outer { public: template <typename InType> class Inner { public: template <typename X> void nested(); }; };The class template
Outer
defines a nested class template
Inner
. Inner
in turn defines a template member function.
Next a class template Usage
is defined, offering a member function
caller
expecting an object of the above Inner
type. An initial setup
for Usage
looks like this:
template <typename T1, typename T2> class Usage { public: void caller(Outer<T1>::Inner<T2> &obj); ... };The compiler won't accept this as it interprets
Outer<T1>::Inner
as a
class type. But there is no class Outer<T1>::Inner
. Here the compiler
generates an error like:
error: 'class Outer<T1>::Inner' is not a typeTo inform the compiler that
Inner
itself is a template, using the template type parameter <T2>
, the
::template
construction is required. It tells the compiler that the next
<
should not be interpreted as a `less than' token, but rather as a
template type argument. So, the declaration is modified to:
void caller(Outer<T1>::template Inner<T2> &obj);This still doesn't get us where we want to be: after all
Inner<T2>
is
a type, nested under a class template, depending on a template type
parameter. In fact, the original Outer<T1>::Inner<T2> &obj
declaration
results in a series of error messages, one of them looking like this:
error: expected type-name before '&' tokenAs is often the case this error message nicely indicates what should be done to get it right: add
typename
:
void caller(typename Outer<T1>::template Inner<T2> &obj);
Of course, caller
itself is not only just declared, it must also be
implemented. Assume that its implementation should call Inner
's member
nested
, instantiated for yet another type X
. The class template
Usage
should therefore receive a third template type parameter, called
T3
. Assume it has been defined. To implement caller
, we write:
void caller(typename Outer<T1>::template Inner<T2> &obj) { obj.nested<T3>(); }Once again we run into a problem. In the function's body the compiler once again interprets
<
as `less than', seeing a logical expression having as
its right-hand side a primary expression instead of a function call specifying
a template type T3
.
To tell the compiler that is should interpret <T3>
as a type to
instantiate, the template
keyword must once again be used. This
time it is used in the context of the member selection operator. We write
.template
to inform the compiler that what follows is not a `less than'
operator, but rather a type specification. The function's final implementation
becomes:
void caller(typename Outer<T1>::template Inner<T2> &obj) { obj.template nested<T3>(); }
Instead of defining value or reference parameters functions may also
define pointer parameters. Had obj
been defined as a pointer parameter the
implementation would have had to use the ->template
construction, rather
than the .template
construction. E.g.,
void caller(typename Outer<T1>::template Inner<T2> *ptr) { ptr->template nested<T3>(); }
enum
values. Enums are preferred over, e.g., int const
values since enums never
require any linkage. They are pure symbolic values with no memory
representation whatsoever.
Consider the situation where a programmer must use a cast, say a
reinterpret_cast
. A problem with a reinterpret_cast
is that it is the
ultimate way to turn off all compiler checks. All bets are off, and we can
write extreme but absolutely pointless reinterpret_cast
statements, like
int intVar = 12; ostream &ostr = reinterpret_cast<ostream &>(intVar);
Wouldn't it be nice if the compiler would warn us against such oddities by generating an error message?
If that's what we'd like the compiler to do, there must be some way to
distinguish madness from weirdness. Let's assume we agree on the following
distinction: reinterpret casts are never acceptable if the target type
represents a larger type than the expression (source) type, since that would
immediately result in exceeding the amount of memory that's actually available
to the target type. For this reason it's clearly silly to
reinterpret_cast<double *>(&intVar)
, but reinterpret_cast<char
*>(&intVar)
could be defensible.
The intent is now to create a new kind of cast, let's call it
reinterpret_to_smaller_cast
. It should only be allowed to perform a
reinterpret_to_smaller_cast
if the target type occupies less memory than
the source type (note that this exactly the opposite reasoning as used by
Alexandrescu (2001), section 2.1).
To start, we construct the following template:
template<typename Target, typename Source> Target &reinterpret_to_smaller_cast(Source &source) { // determine whether Target is smaller than source return reinterpret_cast<Target &>(source); }
At the comment an enum-definition is inserted defining a symbol having a
suggestive name. A compile-time error results if the required condition is
not met and the error message displays the name of the symbol. A division by
zero is clearly not allowed, and noting that a false
value represents a
zero value, the condition could be:
1 / (sizeof(Target) <= sizeof(Source));The interesting part is that this condition doesn't result in any code at all. The enum's value is a plain value that's computed by the compiler while evaluating the expression:
template<typename Target, typename Source> Target &reinterpret_to_smaller_cast(Source &source) { enum { the_Target_size_exceeds_the_Source_size = 1 / (sizeof(Target) <= sizeof(Source)) }; return reinterpret_cast<Target &>(source); }When
reinterpret_to_smaller_cast
is used to cast from int
to
double
an error is produced by the compiler, like this:
error: enumerator value for 'the_Target_size_exceeds_the_Source_size' is not an integer constantwhereas no error is reported if, e.g.,
reinterpret_to_smaller_cast<int>(doubleVar)
is requested with
doubleVar
defined as a double
.
In the above example an enum
was used to compute (at compile-time) a
value that is illegal if an assumption is not met. The creative part is
finding an appropriate expression.
Enum values are well suited for these situations as they do not consume any memory and their evaluation does not produce any executable code. They can be used to accumulate values too: the resulting enum value then contains a final value, computed by the compiler rather than by executable code as the next sections illustrate. In general, programs shouldn't do run-time what they can do at compile-time and performing complex calculations resulting in constant values is a clear example of this principle.
int
values. This is useful in situations where a scalar value (often a
bool
value) is available to select a specialization but a type is required
to base the selection on. This situation is shortly encountered (section
23.2.2).
Templatizing
integral values is based on the fact that a
class template together with its template arguments defines a type. E.g.,
vector<int>
and vector<double>
are different types.
Turning integral values into templates is easily done. Define a template (it
does not have to have any contents at all) and store the integral value in an
enum
:
template <int x> struct IntType { enum { value = x }; };As
IntType
does not have any members the `class IntType
' can be
defined as `struct IntType
', saving us from having to type public:
.
Defining the enum
value `value
' allows us to retrieve the value
used at the instantiation at no cost in storage. Enum values are neither
variables nor data members and thus have no address. They are mere values.
It's easy to use the struct IntType
. An anonymous or named
object can be defined by specifying a value for its int
non-type
parameter. Example:
int main() { IntType<1> it; cout << "IntType<1> objects have value: " << it.value << "\n" << "IntType<2> objects are of a different type " "and have values " << IntType<2>().value << '\n'; }Actually, neither the named object nor the anonymous object is required. As the
enum
is defined as a plain value, associated with the
struct IntType
we merely have to specify the specific int
for which
the struct IntType
is defined to retrieve its `value
', like this:
int main() { cout << "IntType<100>, no object, defines `value': " << IntType<100>::value << "\n"; }
if
and
switch
statements. If we want to be able to `program the compiler'
this feature must also be offered by templates.
Like templates storing values templates making choices do not require any code to be executed at run-time. The selection is purely made by the compiler, at compile-time. The essence of template meta programming is that we are not using or relying on any executable code. The result of a template meta program often is executable code, but that code is a function of decisions merely made by the compiler.
Template (member) functions are only instantiated when they are actually used. Consequently we can define specializations of functions that are mutually exclusive. Thus it is possible to define a specialization that can be compiled in situation one, but not in situation two and to define another specialization that can be compiled in situation two, but not in situation one. Using specializations code can be generated that is tailored to the demands of a particular situation.
A feature like this cannot be implemented in run-time executable code. For example, when designing a generic storage class the software engineer may intend to store value class type objects as well as objects of polymorphic class types in the final storage class. Thus the software engineer may conclude that the storage class should contain pointers to objects, rather than the objects themselves. The initial implementation attempt could look like this:
template <typename Type> void Storage::add(Type const &obj) { d_data.push_back( d_ispolymorphic ? obj.clone() : new Type(obj) ); }The intent is to use the
clone
member function of the class Type
if Type
is a polymorphic class and the standard copy constructor if
Type
is a value class.
Unfortunately, this scheme usually fails as value classes do not define
clone
member functions and polymorphic base classes should delete
their copy constructors (cf. section 7.6). It doesn't matter to the
compiler that clone
is never called for value classes and that the copy
constructor is only available in value classes and not in polymorphic
classes. It merely has some code to compile, and can't do that because of
missing members. It's as simple as that.
add
member functions of which only one is going to be called
(and thus instantiated). Our selection will be based on an additional (in
addition to Type
itself) template non-type parameter that indicates
whether we'll use Storage
for polymorphic or non-polymorphic classes. Our
class Storage
starts like this:
template <typename Type, bool isPolymorphic> class StorageInitially two overloaded versions of our
add
member are defined:
one used with Storage
objects storing polymorphic objects (using true
as its template non-type argument) and one storing value
class objects (using false
as its template non-type argument).
Unfortunately we run into a small problem: functions cannot be overloaded
by their argument values but only by their argument types. But the
small problem may be solved. Realizing that types are defined by the
combination of template names and their template arguments we may convert the
values true
and false
into types using the knowledge from section
23.2.1.1 about how to convert integral values to types.
We'll provide one (private) add
member with a IntType<true>
parameter
(implementing the polymorphic class) and another (private) add
member with
a IntType<false>
parameter (implementing the non-polymorphic class).
In addition to these two private members a third (public) member add
is
defined calling the appropriate private add
member by providing an
IntType
argument, constructed from Storage
's template non-type
parameter.
Here are the implementations of the three add
members:
// declared in Storage's private section: template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj, IntType<true>) { d_data.push_back(obj.clone()); } template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj, IntType<false>) { d_data.push_back(new Type(obj)); } // declared in Storage's public section: template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj) { add(obj, IntType<isPolymorphic>()); }The appropriate
add
member is instantiated and called because a
primitive value can be converted to a type. Each of the possible template
non-type values is thus used to define an overloaded class template member
function.
Since class template members are only instantiated when used only one of
the overloaded private add
members is instantiated. Since the other one is
never called (and thus never instantiated) compilation errors are prevented.
Storage
class that uses pointers to store copies of value class
objects. Their argument is that value class objects can very well be stored by
value, rather than by pointer. They'd rather store value class objects by
value and polymorphic class objects by pointer.
Such distinctions frequently occur in template meta programming and
the following struct IfElse
may be used to obtain one of two types, depending on a bool
selector
value.
First define the generic form of the template:
template<bool selector, typename FirstType, typename SecondType> struct IfElse { typedef FirstType type; };Then define a partial specialization. The specialization represents a specific selector value (e.g.,
false
) and leaves the remaining types
open to further specification:
template<typename FirstType, typename SecondType> struct IfElse<false, FirstType, SecondType> { typedef SecondType type; };The former (generic) definition associates
FirstType
with the
IfElse::type
type definition, the latter definition (partially specialized
for the logical value false
) associates SecondType
with the
IfElse::type
type definition.
The IfElse
template allows us to define class templates whose data
organization is conditional to the template's parameters.
Using IfElse
the Storage
class may define
pointers to store copies of polymorphic class type objects and values
to store value class type objects:
template <typename Type, bool isPolymorphic> class Storage { typedef typename IfElse<isPolymorphic, Type *, Type>::type DataType; std::vector<DataType> d_data; private: void add(Type const &obj, IntType<true>); void add(Type const &obj, IntType<false>); public: void add(Type const &obj); } template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj, IntType<true>) { d_data.push_back(obj.clone()); } template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj, IntType<false>) { d_data.push_back(obj); } template <typename Type, bool isPolymorphic> void Storage<Type, isPolymorphic>::add(Type const &obj) { add(obj, IntType<isPolymorphic>()); }The above example uses
IfElse
's type
, defined by IfElse
as
either FirstType
or SecondType
. IfElse
's type
defines the
actual data type to use for Storage
's vector
data type.
The remarkable result in this example is that the data organization of
the Storage
class now depends on its template arguments. Since the
isPolymorphic == true
situation uses different data types than the
isPolymorphic == false
situation, the overloaded private add
members
can utilize this difference immediately. E.g., add(Type const &obj,
IntType<false>)
uses direct copy construction to store a copy of obj
in d_vector
.
It is also possible to make a selection from multiple types as IfElse
structs can be nested. Realize that using IfElse
never has any effect on
the size or execution time of the final executable program. The final program
simply contains the appropriate type, conditional to the type that's
eventually selected.
MapType
as a map having plain types or
pointers for either its key or value types, illustrates this approach:
template <typename Key, typename Value, int selector> class Storage { typedef typename IfElse< selector == 1, // if selector == 1: map<Key, Value>, // use map<Key, Value> typename IfElse< selector == 2, // if selector == 2: map<Key, Value *>, // use map<Key, Value *> typename IfElse< selector == 3, // if selector == 3: map<Key *, Value>, // use map<Key *, Value> // otherwise: map<Key *, Value *> // use map<Key *, Value *> >::type >::type >::type MapType; MapType d_map; public: void add(Key const &key, Value const &value); private: void add(Key const &key, Value const &value, IntType<1>); ... }; template <typename Key, typename Value, int selector> inline void Storage<selector, Key, Value>::add(Key const &key, Value const &value) { add(key, value, IntType<selector>()); }The principle used in the above examples is: if class templates may use data types that depend on template non-type parameters, an
IfElse
struct
can be used to select the appropriate data types. Knowledge about the various
data types may also be used to define overloaded member functions. The
implementations of these overloaded members may then be optimized to the
various data types. In programs only one of these alternate functions (the one
that is optimized to the actually used data types) will then be instantiated.
The private add
functions define the same parameters as the public
add
wrapper function, but add a specific IntType
type, allowing the
compiler to select the appropriate overloaded version based on the template's
non-type selector parameter.
for
or while
statement. However, iterations
can always be rewritten as recursions. Recursions are supported
by templates and so iterations can always be implemented as (tail) recursions.
To implement iterations by (tail) recursion do as follows:
enum
values.
Most readers are probably familiar with the recursive implementation of
the mathematical `factorial' operator, commonly represented by the
exclamation mark (!
). Factorial n
(so: n!
) returns the successive
products n * (n - 1) * (n - 2) * ... * 1
, representing the number of ways
n
objects can be permuted. Interestingly, the factorial operator is itself
usually defined by a recursive definition:
n! = (n == 0) ? 1 : n * (n - 1)!To compute
n!
from a template, a template Factorial
can be defined
using an int n
template non-type parameter. A specialization is defined
for the case n == 0
. The generic implementation uses recursion according
to the factorial definition. Furthermore, the Factorial
template defines
an enum
value `value
' containing its factorial value. Here is the
generic definition:
template <int n> struct Factorial { enum { value = n * Factorial<n - 1>::value }; };Note how the expression assigning a value to `
value
' uses constant
values that can be determined by the compiler. The value n is provided, and
Factorial<n - 1>
is computed using template meta
programming. Factorial<n-1>
in turn results in value that can be
determined by the compiler (viz.
Factorial<n-1>::value
). Factorial<n-1>::value
represents the value
defined by the type Factorial<n - 1>
. It is not the value returned
by an object of that type. There are no objects here but merely values
defined by types.
The recursion ends in a specialization. The compiler selects the specialization (provided for the terminating value 0) instead of the generic implementation whenever possible. Here is the specialization's implementation:
template <> struct Factorial<0> { enum { value = 1 }; };The
Factorial
template can be used to determine, compile time, the
number of permutations of a fixed number of objects. E.g.,
int main() { cout << "The number of permutations of 5 objects = " << Factorial<5>::value << "\n"; }Once again,
Factorial<5>::value
is not evaluated at run-time, but
at compile-time. The run-time equivalent of the above cout
statement is,
therefore:
int main() { cout << "The number of permutations of 5 objects = " << 120 << "\n"; }
template <char ...Chars> Type operator "" _identifier()This variadic non-type parameter function template defines no parameters, but merely a variadic non-type parameter list.
Its argument must be an int constant, as is also expected by the literal
operator defining an unsigned long long int
parameter. All the characters
of the int constant are passed as individual char
non-type template
arguments to the literal operator.
For example, if _NM2km
is a literal operator function template, it can
be called as 80_NM2km
. The function template is then actually called as
_NM2km<'8', '0'>()
. If this function template merely uses template meta
programming techniques and only processes integral data then its actions can
be performed completely at compile-time. To illustrate this, let's assume
NM2km
only processes and returns unsigned values.
The function template _NM2km
can forward its argument to a class template,
defining an enum constant value
, and that performs the required
computations. Here is the implementation of the variadic literal operator
function template _NM2km
:
template <char ... Chars> size_t constexpr operator "" _NM2km() { return static_cast<size_t>( // forward Chars to NM2km NM2km<0, Chars ...>::value * 1.852); }The class template
NM2km
defines three non-type parameters: acc
accumulates the value, c
is the first character of the variadic non-type
parameters, while ...Chars
represents the remaining non-type parameters,
contained in a non-type parameter pack. Since c
is, at each recursive
call, the next character from the original non-type parameter pack, the value
so far multiplied by 10 plus the value of the next character is passed as the
next accumulated value to its recursive call, together with the remaining
elements of the parameter pack, represented by Chars ...
:
template <size_t acc, char c, char ...Chars> struct NM2km { enum { value = NM2km<10 * acc + c - '0', Chars ...>::value }; };Eventually, the parameter pack is empty. For this case a partial specialization of
NM2km
is available:
template <size_t acc, char c> // empty parameter pack struct NM2km<acc, c> { enum { value = 10 * acc + c - '0' }; };
This works fine, but of course not in cases where binary, octal, or
hexadecimal values must also be interpreted. In that case we must first
determine whether the first character(s) indicate a special number
system. This can be determined by the class template NM2kmBase
, that is
now called from the _NM2km
literal operator:
template <char ... Chars> size_t constexpr operator "" _NM2km() { return static_cast<size_t>( // forward Chars to NM2kmBase NM2kmBase<Chars ...>::value * 1.852); }The
NM2kmBase
class template normally assumes the decimal number
system, passing base value 10 and initial sum 0 to NM2km
. The NM2km
class template is provided with an additional (first) non-type parameter
representing the base value of the number system to use. Here is
NM2kmBase
:
template <char ...Chars> struct NM2kmBase { enum { value = NM2km<10, 0, Chars ...>::value }; };Partial specializations handle the different number systems, by inspecting the first (one or two) characters:
template <char ...Chars> struct NM2kmBase<'0', Chars ...> // "0..." { enum { // octal value: base 8 value = NM2km<8, 0, Chars ...>::value }; }; template <char ...Chars> struct NM2kmBase<'0', 'b', Chars ...> // "0b..." { enum { // binary value: base 2 value = NM2km<2, 0, Chars ...>::value }; }; template <char ...Chars> struct NM2kmBase<'0', 'x', Chars ...> // "0x..." { enum { // hex value: base 16 value = NM2km<16, 0, Chars ...>::value }; };
NM2km
is implemented as before, albeit that it can now handle
various number systems. The conversion from character to numeric value is left
to a small support function template, cVal
:
template <char c> int constexpr cVal() { return '0' <= c <= '9' ? c - '0' : 10 + c - 'a'; } template <size_t base, size_t acc, char c, char ...Chars> struct NM2km { enum { value = NM2km<base, base * acc + cVal<c>(), Chars ...>::value }; }; template <size_t base, size_t acc, char c> struct NM2km<base, acc, c> { enum { value = base * acc + cVal<c>() }; };
Storage
. Data stored in Storage
objects may either make
and store copies of the data or store the data as received. Storage
objects may also either use a vector or a linked list as its underlying
storage medium. How should the engineer tackle this request? Should four
different Storage
classes be designed?
The engineer's first reaction could be to develop an all-in Storage
class.
It could have two data members, a list and a vector, and its constructor could
be provided with maybe an enum value indicating whether the data itself or new
copies should be stored. The enum value can be used to initialize a series of
pointers to member functions performing the requested tasks (e.g., using a
vector to store the data or a list to store copies).
Complex, but doable. Then the engineer is asked to modify the class: in the
case of new copies a custom-made allocation scheme should be used rather than
the standard new
operator. He's also asked to allow the use of yet
another type of container, in addition to the vector and the list that were
already part of the design. Maybe a deque
would be preferred or maybe even
a stack
.
It's clear that the approach aiming at implementing all functionality and all
possible combinations in one class doesn't scale. The class Storage
soon
becomes a monolithic giant which is hard to understand, maintain, test, and
deploy.
One of the reasons why the big, all-encompassing class is hard to deploy and understand is that a well-designed class should enforce constraints: the design of the class should, by itself, disallow certain operations, violations of which should be detected by the compiler, rather than by a program that might terminate in a fatal error.
Think about the above request. If the class offers both an interface to access
the vector data storage and an interface to access the list data storage,
then it's likely that the class offers an overloaded operator[]
member
to access elements in the vector. This member, however, will be syntactically
present, but semantically invalid when the list data storage is selected,
which doesn't support operator[]
.
Sooner or later, users of the monolithic all-encompassing class
Storage
will fall into the trap of using operator[]
even though
they've selected the list as the underlying data storage. The compiler won't
be able to detect the error, which only appears once the program is
running, confusing its users.
The question remains: how should the engineer proceed, when confronted with the above questions? It's time to introduce policies.
In the previous section the problem of creating a class that might use any of a series of allocation schemes was introduced. These allocation schemes all depend on the actual data type to use, and so the `template reflex' should kick in.
Allocation schemes should probably be defined as template classes, applying
the appropriate allocation procedures to the data type at hand. When such
allocation schemes are used by the familiar STL containers (like
std::vector, std::stack
, etc.), then such home-made allocation schemes
should probably be derived from std::allocator
, to provide
for the requirements made by these containers. The class template
std::allocator
is declared by the <memory>
header file and the three
allocation schemes developed here were all derived from std::allocator
.
Using in-class implementations for brevity the following allocation classes could be defined:
Data
is used `as is':
template <typename Data> class PlainAlloc: public std::allocator<Data> { template<typename IData> friend std::ostream &operator<<(std::ostream &out, PlainAlloc<IData> const &alloc); Data d_data; public: PlainAlloc() {} PlainAlloc(Data const &data) : d_data(data) {} PlainAlloc(PlainAlloc<Data> const &other) : d_data(other.d_data) {} };
new
operator to
allocate a new copy of the data:
template <typename Data> class NewAlloc: public std::allocator<Data> { template<typename IData> friend std::ostream &operator<<(std::ostream &out, NewAlloc<IData> const &alloc); Data *d_data; public: NewAlloc() : d_data(0) {} NewAlloc(Data const &data) : d_data(new Data(data)) {} NewAlloc(NewAlloc<Data> const &other) : d_data(new Data(*other.d_data)) {} ~NewAlloc() { delete d_data; } };
request
,
obtaining the required amount of memory, is left as an exercise to the
reader):
template<typename Data> class PlacementAlloc: public std::allocator<Data> { template<typename IData> friend std::ostream &operator<<(std::ostream &out, PlacementAlloc<IData> const &alloc); Data *d_data; static char s_commonPool[]; static char *s_free; public: PlacementAlloc() : d_data(0) {} PlacementAlloc(Data const &data) : d_data(new(request()) Data(data)) {} PlacementAlloc(PlacementAlloc<Data> const &other) : d_data(new(request()) Data(*other.d_data)) {} ~PlacementAlloc() { d_data->~Data(); } private: static char *request(); };
Storage
introduced in the previous section. In addition
to these classes, additional allocation schemes could be implemented by the
user as well.
To apply the proper allocation scheme to the class Storage
,
Storage
should be designed as a class template itself. The class also
needs a template type parameter allowing users to specify the data type.
The data type to be used by a particular allocation scheme could of course
be specified when specifying the allocation scheme to use. The class
Storage
would then have two template type parameters, one for the data
type, one for the allocation scheme:
template <typename Data, typename Scheme> class Storage ...
To use the class Storage
we would then write, e.g.:
Storage<string, NewAlloc<string>> storage;Using
Storage
this way is fairly complex and potentially error-prone,
as it requires the user to specify the data type twice. Instead, the
allocation scheme should be specified using a new type of template parameter,
not requiring the user to specify the data type required by the allocation
scheme. This new kind of template parameter (in addition to the well-known
template type parameter and template non-type parameter) is called the
template template parameter.
Starting with the C++14 standard using the keyword class
in the syntactical form of template template parameters (template
<parameter specifications> class Name
) is no longer required. From that
standard onward, the keyword typename
can also be used (e.g., template
<parameter specifications> typename Name
).
To specify an allocation policy, rather than an allocation type
for the class Storage
we rephrase its class template header:
definition starts as follows:
template <typename Data, template <typename> class Policy> class Storage...The second template parameter is new. It is a template template parameter. It has the following elements:
template
, starting the template template parameter;
template
is followed (between pointed brackets) by a
list of template parameters that must be specified for the template
template parameter. These parameters may be given names, but names
are usually omitted as those names cannot be used in subsequent
template definitions. On the other hand, providing formal names may
help the reader of the template to understand the kind of templates
that must be specified with the template template parameter.
class
must be
specified. In this case, typename
can not be used. However, in the upcoming C++17 standard this
restriction will most likely be removed from the language.
template < template < typename = std::string, int = 12, template <typename = int> class Inner = std::vector > class Policy > class Demo { ... };Here, the class template
Demo
expects a template template parameter
named Policy
, expecting three template parameters: a template type
parameter (by default std::string
); a template non-type parameter
(by default having value 12); and Policy
itself expects a template
template parameter, called Inner
, by default using an int
as
its template type parameter.
Policy
could be used as a base class of the class
Storage
.
The policy operates on the class Storage
's data type. Therefore the
policy is informed about that data type as well. Our class Storage
now
begins like this:
template <typename Data, template <typename> class Policy> class Storage: public Policy<Data>This automatically allows us to use
Policy
's members when implementing
the members of the class Storage
.
Our home-made allocation classes do not really provide us with many useful
members. Except for the extraction operator they offer no immediate access to
the data. This can easily be repaired by adding more members. E.g., the class
NewAlloc
could be augmented with operators allowing access to and
modification of stored data:
operator Data &() // optionally add a `const' member too { return *d_data; } NewAlloc &operator=(Data const &data) { *d_data = data; }The other allocation classes could be given comparable members.
Let's use the allocation schemes in some real code. The next
example shows how Storage
can be defined using some data type and an
allocation scheme. We start out again with a class Storage
:
template <typename Data, template <typename> class Allocate> class Storage: public std::vector<Data, Allocate<Data>> {};That's all we have to do. Note that
std::vector
formally has two
template parameters. The first one is the vector's data type, which is always
specified; the second one is the allocator used by the vector. Usually the
allocator is left unspecified (in which case the default STL allocator is
used), but here it is mentioned explicitly, allowing us to pass our own
allocation policy to Storage
.
All required functionality is inherited from the vector
base class, while
the policy is `factored into the equation' using a template template
parameter. Here's an example showing how this is done:
Storage<std::string, NewAlloc> storage; copy(istream_iterator<std::string>(cin), istream_iterator<std::string>(), back_inserter(storage)); cout << "Element index 1 is " << storage[1] << '\n'; storage[1] = "hello"; copy(storage.begin(), storage.end(), ostream_iterator<NewAlloc<std::string> >(cout, "\n"));Since
Storage
objects are also std::vector
objects the STL copy
function can be used in combination with the back_inserter iterator to add
some data to the storage
object. Its elements can be accessed and modified
using the index operator. Then NewAlloc<std::string>
objects are inserted
into cout
(also using the copy
function).
Interestingly, this is not the end of the story. Remember that our
intention was to create a class allowing us to specify the storage type as
well. What if we don't want to use a vector
, but instead would like to use
a list
?
It's easy to change Storage
's setup so that a completely different
storage type can be used on request, like a deque
. To implement this, the
storage class is parameterized as well, using yet another template template
parameter:
template <typename Data, template <typename> class AllocatonPolicy, template <typename, typename> class Container = std::vector> class Storage: public Container<Data, AllocationPolicy<Data>> {};The earlier example using a
Storage
object can be used again without
requiring any modifications at all (except for the above redefinition). It
clearly can't be used with a list
container, as the list
lacks
operator[]
. Trying to do so is immediately recognized by the compiler,
producing an error if an attempt is made to use operator[]
on, e.g., a
list
. (A complete example showing the definition of the
allocation classes and the class Storage
as well as its use is provided in
the Annotation's distribution in the file
yo/advancedtemplates/examples/storage.cc
.) A list
container, however
can still be specified as the container to use. In that case a Storage
is
implemented as a list
, offering list
's interface, rather than
vector
's interface, to its users.
This situation, although legal, should be avoided for various reasons:
vtable
is
required as well as a data member pointing to the vtable;
By providing a well-defined interface a class derived from a policy class may
define member specializations using the different structures of policy classes
to their advantage. For example, a plain pointer-based policy class could
offer its functionality by resorting to C-style pointer juggling,
whereas a vector
-based policy class could use the vector's members
directly.
In this example a generic class template Size
could be designed
expecting a container-like policy using features commonly found in
containers, defining the data (and hence the structure) of the container
specified in the policy. E.g.:
template <typename Data, template <typename> class Container> struct Size: public Container<Data> { size_t size() { // relies on the container's `size()' // note: can't use `this->size()' return Container<Data>::size(); } };A specialization can now be defined for a much simpler storage class using, e.g., plain pointers (the implementation capitalizes on
first
and
second
, data members of std::pair
. Cf. the example at the end of this
section):
template <typename Data> struct Size<Data, Plain>: public Plain<Data> { size_t size() { // relies on pointer data members return this->second - this->first; } };Depending on the intentions of the template's author other members could be implemented as well.
To simplify the real use of the above templates, a generic wrapper class
can be constructed: it uses the Size
template matching the actually used
storage type (e.g., a std::vector
or some plain storage class) to define
its structure:
template <typename Data, template <typename> class Store> class Wrapper: public Size<Data, Store> {};
The above classes could now be used as follows (en passant showing an
extremely basic Plain
class):
#include <iostream> #include <vector> template <typename Data> struct Plain: public std::pair<Data *, Data *> {}; int main() { Wrapper<int, std::vector> wiv; std::cout << wiv.size() << "\n"; Wrapper<int, Plain> wis; std::cout << wis.size() << "\n"; }The
wiv
object now defines vector-data, the wis
object merely
defines a std::pair
object's data members.
Template aliases can be used as arguments to template template
parameters. This allows us to avoid the `unexpected default parameters' you
may encounter when using template template parameters. E.g., defining a
template specifying a template <typename> class Container
is fine, but it
is impossible to specify a container like vector
or set
as template
template argument, as vector
and set
containers also define a second
template parameter, specifying their allocation policy.
Template aliases are defined as using
declarations, specifying an alias
for an existing (maybe partially or fully specialized) template type. In the
following example Vector
is defined as an alias for vector
:
template <typename Type> using Vector = std::vector<Type>; Vector<int> vi; // same as std::vector<int> std::vector<int> vi2(vi); // copy construction: OKSo, what's the point of doing this? Looking at the
vector
container, we see that it defines two, rather
than one, template parameters, the second parameter being the allocation
policy _Alloc
, by default set to std::allocator<_Tp>
:
template<typename _Tp, typename _Alloc = std::allocator<_Tp> > class vector: ...Now define a class template
Generic
defining a template template
parameter:
template <typename Type, template <typename> class Container> class Generic: public Container<Type> { ... };Most likely,
Generic
offers members made available by the container
that is actually used to create the Generic
object, and adds to those some
members of it own. However, a simple container like std::vector
cannot be
used, as std::vector
doesn't match a template <typename> class
Container>
parameter; it requires a template <typename, typename> class
Container>
template template parameter.
The Vector
template alias, however, is defined as a template
having one template type parameter, and it uses the vector's default
allocator. Consequently, passing a Vector
to Generic
works fine:
Generic<int, Vector> giv; // OK Generic<int, std::vector> err; // won't compile: 2nd argument mismatch
With the aid of a small template alias it is also possible to use a
completely different kind of container, like a map
, with Generic
:
template <typename Type> using MapString = std::map<Type, std::string>; Generic<int, MapString> gim; // uses map<int, string>
std
namespace
trait classes are found. E.g., most C++ programmers have seen
the compiler mentioning `std::char_traits<char>
' when performing an
illegal operation on std::string
objects, as in std::string s(1)
.
Trait classes are used to make compile-time decisions about types. Trait
classes allow us to apply the proper code to the proper data type, be it a
pointer, a reference, or a plain value, all this maybe in combination with
const
. The particular type of data to use can be inferred from the actual
type that is specified (or implied) when the template is used. This can be
fully automated, not requiring the template writer to make any decision.
Trait classes allow us to develop a template <typename Type1, typename
Type2, ...>
without the need to specify many specializations covering all
combinations of, e.g., values, (const) pointers, or (const) references, which
would soon result in an unmaintainable exponential explosion of template
specializations (e.g., allowing these five different types for each template
parameter already results in 25 combinations when two template type parameters
are used: each must be covered by potentially different specializations).
Having available a trait class, the actual type can be inferred compile
time, allowing the compiler to deduce whether or not the actual type is a
pointer, a pointer to a member, or a const pointer, and to make comparable
deductions in case the actual type is, e.g., an lvalue or rvalue reference
type. This in turn allows us to write templates that define types like
argument_type
, first_argument_type
, second_argument_type
and
result_type
, which are required by several generic algorithms (e.g.,
count_if()).
A trait class usually performs no behavior. I.e., it has no constructor
and no members that can be called. Instead, it defines a series of types and
enum
values that have certain values depending on the actual type that is
passed to the trait class template. The compiler uses one of a set of
available specializations to select the one appropriate for an actual template
type parameter.
The point of departure when defining a trait template is a plain
vanilla struct
, defining the characteristics of a plain value type like
an int
. This sets the stage for specific specializations, modifying the
characteristics for any other type that could be specified for the template.
To make matters concrete, assume the intent is to create a trait class
BasicTraits
telling us whether a type is a plain value type, a pointer
type, an lvalue reference type or an rvalue reference type (all of which may
or may not be const
types).
Whatever the actually provided type, we want to be able to determine the `plain' type (i.e., the type without any modifiers, pointers or references), the `pointer type' and the `reference type', allowing us to define in all cases, e.g., an rvalue reference to its built-in type, even though we passed a const pointer to that type.
Our point of departure, as mentioned, is a plain struct
defining the
required parameter. Maybe something like this:
template <typename T> struct Basic { typedef T Type; enum { isPointer = false, isConst = false, isRef = false, isRRef = false }; };
Although some conclusions can be drawn by combining various enum
values (e.g., a plain type is not a pointer or a reference or a rvalue
reference or a const), it is good practice to provide a full implementation of
trait classes, not requiring its users to construct these logical expressions
themselves. Therefore, the basic decisions in a trait class are usually made
by a
nested trait class,
leaving the task of creating appropriate logical expressions to a
surrounding trait class.
So, the struct Basic
defines the generic form of our inner trait
class. Specializations handle specific details. E.g., a pointer type is
recognized by the following specialization:
template <typename T> struct Basic<T *> { typedef T Type; enum { isPointer = true, isConst = false, isRef = false, isRRef = false }; };
whereas a pointer to a const type is matched with the next specialization:
template <typename T> struct Basic<T const *> { typedef T Type; enum { isPointer = true, isConst = true, isRef = false, isRRef = false }; };
Several other specializations should be defined: e.g., recognizing
const
value types or (rvalue) reference types. Eventually all these
specializations are implemented as nested struct
s of an outer class
BasicTraits
, offering the public traits class interface. The outline of
the outer trait class is:
template <typename TypeParam> class BasicTraits { // Define specializations of the template `Base' here public: BasicTraits(BasicTraits const &other) = delete; typedef typename Basic<TypeParam>::Type ValueType; typedef ValueType *PtrType; typedef ValueType &RefType; typedef ValueType &&RvalueRefType; enum { isPointerType = Basic<TypeParam>::isPointer, isReferenceType = Basic<TypeParam>::isRef, isRvalueReferenceType = Basic<TypeParam>::isRRef, isConst = Basic<TypeParam>::isConst, isPlainType = not (isPointerType or isReferenceType or isRvalueReferenceType or isConst) }; };The trait class's public interface explicitly deletes its copy constructor. As it therefore defines no constructor at all and as it has no static members it does not offer any run-time executable code. All the trait class's facilities must therefore be used compile time.
A trait class template can be used to obtain the proper type, irrespective
of the template type argument provided. It can also be used to select
a proper specialization that depends on, e.g., the const
-ness of a
template type. Example:
cout << "int: plain type? " << BasicTraits<int>::isPlainType << "\n" "int: ptr? " << BasicTraits<int>::isPointerType << "\n" "int: const? " << BasicTraits<int>::isConst << "\n" "int *: ptr? " << BasicTraits<int *>::isPointerType << "\n" "int const *: ptr? " << BasicTraits<int const *>::isPointerType << "\n" "int const: const? " << BasicTraits<int const>::isConst << "\n" "int: reference? " << BasicTraits<int>::isReferenceType << "\n" "int &: reference? " << BasicTraits<int &>::isReferenceType << "\n" "int const &: ref ? " << BasicTraits<int const &>::isReferenceType << "\n" "int const &: const ? " << BasicTraits<int const &>::isConst << "\n" "int &&: r-reference? " << BasicTraits<int &&>::isRvalueReferenceType << "\n" "int &&: const? " << BasicTraits<int &&>::isConst << "\n" "int const &&: r-ref ? "<< BasicTraits<int const &&>:: isRvalueReferenceType << "\n" "int const &&: const ? "<< BasicTraits<int const &&>::isConst << "\n" "\n"; BasicTraits<int *>::ValueType value = 12; BasicTraits<int const *>::RvalueRefType rvalue = int(10); BasicTraits<int const &&>::PtrType ptr = new int(14); cout << value << ' ' << rvalue << ' ' << *ptr << '\n';
TypeTrait
trait class was developed. Using
specialized versions of a nested struct Type
modifiers, pointers,
references and values could be distinguished.
Knowing whether a type is a class type or not (e.g., the type represents a primitive type) could also be a useful bit of knowledge to a template developer. The class template developer might want to define a specialization when the template's type parameter represents a class type (maybe using some member function that should be available) and another specialization for non-class types.
This section addresses the question how a trait class can distinguish class types from non-class types.
In order to distinguish classes from non-class types a distinguishing feature that can be used at compile-time must be found. It may take some thinking to find such a distinguishing characteristic, but a good candidate eventually is found in the pointer to members syntactic construct. Pointers to members are only available for classes. Using the pointer to member construct as the distinguishing characteristic, a specialization can be developed that uses the pointer to member if available. Another specialization (or the generic template) does something else if the pointer to member construction is not available.
How can we distinguish a pointer to a member from `a generic situation', not being a pointer to a member? Fortunately, such a distinction is possible. A function template specialization can be defined having a parameter which is a pointer to a member function. The generic function template then accepts any other argument. The compiler selects the former (specialized) function when the provided type is a class type as class types may support a pointer to a member. The interesting verb here is `may': the class does not have to define a pointer to member.
Furthermore, the compiler does not actually call any function: we're talking compile-time here. All the compiler does is to select the appropriate function by evaluating a constant expression.
So, our intended function template now looks like this:
template <typename ClassType> static `some returntype' fun(void (ClassType::*)());The function's return type (`
(some returntype)
') will be defined
shortly. Let's first have a closer look at the function's parameter. The
function's parameter defines a pointer to a member returning void
. Such a
function does not have to exist for the concrete class-type that's
specified when the function is used. In fact, no implementation is
provided. The function fun
is only declared as a static member in the
trait class. It's not implemented and no trait class object is required to
call it. What, then, is its use?
To answer the question we now have a look at the generic function template that should be used when the template's argument is not a class type. The language offers a `worst case' parameter in its ellipsis parameter list. The ellipsis is a final resort the compiler may turn to if everything else fails. The generic function template specifies a plain ellipsis in its parameter list:
template <typename NonClassType> static `some returntype' fun(...);It would be an error to define the generic alternative as a function expecting an
int
. The compiler, when confronted with alternatives,
favors the simplest, most specified alternative over a more complex, generic
one. So, when providing fun
with an argument it selects int
whenever possible and it won't select fun(void (ClassType::*)())
. When
given the choice between fun(void (ClassType::*)())
and fun(...)
it
selects the former unless it can't do that.
The question now becomes: what argument can be used for both a pointer to a member and for the ellipsis? Actually, there is such a `one size fits all' argument: 0. The value 0 can be passed as argument value to functions defining an ellipsis parameter and to functions defining a pointers-to-member parameter.
But 0 does not specify a particular class. Therefore, fun
must specify
an explicit template argument, appearing in our code as fun<Type>(0)
, with
Type
being the template type parameter of the trait class.
Now for the return type. The function's return type cannot be a simple
value (like true
or false
). Our eventual intent is to provide the
trait class with an enum telling us whether the trait class's template
argument represents a class type or not. That enum becomes something like
this:
enum { isClass = some class/non-class distinguishing expression } ;The distinguishing expression cannot be
enum { isClass = fun<Type>(0) } ;as
fun<Type>(0)
is not a constant expression and enum values must
be defined by constant expressions so they can be determined at compile-time.
To determine isClass
's value we must find an expression allowing for
compile-time discriminations between fun<Type>(...)
and fun<Type>(void
(Type::*)())
.
In situations like these the sizeof
operator often is our tool of
choice as it is evaluated at compile-time. By defining different sized return
types for the two fun
declarations we are able to distinguish (at
compile-time) which of the two fun
alternatives is selected by the
compiler.
The char
type is by definition a type having size 1. By defining
another type containing two consecutive char
values a larger type is
obtained. A char [2]
is of course not a type, but a char[2]
can be
defined as a data member of a struct, and a struct does define a
type. That struct then has a size exceeding 1. E.g.,
struct Char2 { char data[2]; };
Char2
can be defined as a nested type of our traits class. The
two fun
function template declarations become:
template <typename ClassType> static Char2 fun(void (ClassType::*)()); template <typename NonClassType> static char fun(...);Since
sizeof
expressions are evaluated at compile-time we can now
determine isClass
's value:
enum { isClass = sizeof(fun<Type>(0)) == sizeof(Char2) };This expression has several interesting implications:
fun
function template is ever instantiated;
Type
and selects
fun
's function template specialization if Type
is a class type and the
generic function template if not;
isClass
.
<type_traits>
header file must be included.
All facilities offered by type_traits
are defined in the std
namespace (omitted from the examples given below), allowing programmers to
determine various characteristics of types and values.
In the description of available type traits the following concepts are encountered:
void
or objects;
void
, to objects, to functions, or to
non-static class members;
bool
and all built-in types representing (possibly unicode) characters;
false
unless noexcept(true)
is used at the function's declaration. E.g.,
struct NoThrow { NoThrow &operator=(SomeType const &rhs) noexept(true); };
constexpr
constructor other than the copy or move
constructor, and only has non-static data members and base classes of
literal types;
default
) in
their class interfaces and (for default constructors or assignment
operators) only perform byte-by-byte actions. Here are two examples:
struct Pod
only has trivial members as it doesn't explicitly
declare any member function and its data member is plain old
data. struct Nonpod
is not plain old data. Although it
doesn't explictly declare any member function either, its data member
is a std::string
, which itself isn't plain old data as
std::string
has non-trivial constructors:
struct Pod { int x; }; struct Nonpod { std::string s; };
When type-condion applies to a type, it must be a complete type, void
,
or an array of unknown size;
The following type traits are provided:
add_const<typename Type>::type
to add const
to Type
;
add_cv<typename Type>::type
to add const volatile
to Type
;
add_lvalue_reference<typename Type>::type
to add an lvalue reference to Type
;
add_lvalue_reference<typename Type>::type
to add an lvalue reference to Type
;
add_pointer<typename Type>::type
to add a pointer to Type
;
add_rvalue_reference<typename Type>::type
to add an rvalue reference to Type
;
add_volatile<typename Type>::type
to add volatile
to Type
;
conditional<bool cond, typename TrueType, typename FalseType>::type
to conditionally use TrueType
if cond
is true,
FalseType
if not;
enable_if<bool cond, typename Type>::type
to conditionally define Type
if cond
is true;
has_nothrow_assign<typename Type>::value
to determine whether Type
has an assignment
operator not throwing exceptions;
has_nothrow_copy_constructor<typename Type>::value
to determine whether Type
has a
copy constructor not throwing exceptions;
has_nothrow_default_constructor<typename Type>::value
to determine whether Type
has a
constructor not throwing exceptions;
has_nothrow_destructor<typename Type>::value
to determine whether Type
has a
destructor not throwing exceptions;
has_trivial_assign<typename Type>::value
to determine whether Type
has a trivial
assignment operator;
has_trivial_copy_constructor<typename Type>::value
to determine whether Type
has a
trivial copy constructor;
has_trivial_default_constructor<typename Type>::value
to determine whether Type
has a
trivial default constructor;
has_trivial_destructor<typename Type>::value
to determine whether Type
has a trivial
destructor;
has_virtual_destructor<typename Type>::value
to determine whether Type
has a virtual
destructor;
is_abstract<typename Type>::value
to determine whether Type
is an abstract type
(e.g., an abstract base class) (type-condition applies);
is_arithmetic<typename Type>::value
to determine whether Type
is an arithmetic type;
is_array<typename Type>::value
to determine whether Type
is an array type;
is_assignable<typename To, typename From>::value
to determine whether an object of type From
can
be assigned to an object of type To
(type-condition applies);
is_base_of<typename Base, typename Derived>::value
to determine whether Base
is a base class
of type Derived
;
is_class<typename Type>::value
to determine whether Type
is a class type;
is_compound<typename Type>::value
to determine whether Type
is a compound type;
is_const<typename Type>::value
to determine whether Type
is a const type;
is_constructible<typename Type, typename ...Args>::value
to determine whether Type
is constructible
from arguments in the Args
parameter pack (type-condition
applies to all types in Args
);
is_convertible<typename From, typename To>::value
to determine whether a type From
may be
converted to a type To
using a static_cast
;
is_copy_assignable<typename Type>::value
to determine whether Type
supports copy
assignment (type-condition applies);
is_copy_constructible<typename Type>::value
to determine whether Type
supports copy
construction (type-condition applies);
is_default_constructible<typename Type>::value
to determine whether Type
supports a
default constructor (type-condition applies);
is_destructible<typename Type>::value
to determine whether Type
has a non-deleted
destructor (type-condition applies);
is_empty<typename Type>::value
to determine whether Type
is a class type (not a union
type), without non-static data members, virtual members, virtual or
non-empty base classes (type-condition applies);
is_enum<typename Type>::value
to determine whether Type
is an enum type;
is_floating_point<typename Type>::value
to determine whether Type
is a floating point
type;
is_function<typename Type>::value
to determine whether Type
is a function type;
is_fundamental<typename Type>::value
to determine whether Type
is a fundamental type;
is_integral<typename Type>::value
to determine whether Type
is an integral type;
is_literal_type<typename Type>::value
to determine whether Type
is a literal type
(type-condition applies);
is_lvalue_reference<typename Type>::value
to determine whether Type
is an lvalue
reference;
is_member_function_pointer<typename Type>::value
to determine whether Type
is a
pointer to a non-static member function;
is_member_object_pointer<typename Type>::value
to determine whether Type
is a pointer
to a non-static data member;
is_member_pointer<typename Type>::value
to determine whether Type
is a pointer to a
member function;
is_move_assignable<typename Type>::value
to determine whether Type
supports move
assignment (type-condition applies);
is_move_constructible<typename Type>::value
to determine whether Type
supports move
construction (type-condition applies);
is_nothrow_assignable<typename To, typename From>::value
to determine whether Type
supports an
assignment operator not throwing exceptions (type-condition
applies).
is_nothrow_constructible<typename Type, typename ...Args>::value
to determine whether a Type
object can
be constructed from arguments of types mentioned in the parameter pack
not throwing exceptions (type-condition applies);
is_nothrow_copy_assignable<typename Type>::value
to determine whether Type
supports a
copy-assignment operator not throwing exceptions (type-condition
applies);
is_nothrow_copy_constructible<typename Type>::value
to determine whether Type
supports copy construction not throwing exceptions (type-condition
applies);
is_nothrow_default_constructible<typename Type>::value
to determine whether Type
supports a default constructor not throwing exceptions
(type-condition applies);
is_nothrow_destructible<typename Type>::value
to determine whether Type
supports a
destructor not throwing exceptions (type-condition applies).
is_nothrow_move_assignable<typename Type>::value
to determine whether Type
supports
move assignment not throwing exceptions (type-condition applies);
is_nothrow_move_constructible<typename Type>::value
to determine whether Type
supports a move constructor not throwing exceptions
(type-condition applies);
is_object<typename Type>::value
to determine whether Type
is an object (in contrast
to scalar) type;
is_pod<typename Type>::value
to determine whether Type
is plain old data
(type-condition applies);
is_pointer<typename Type>::value
to determine whether Type
is a pointer type;
is_polymorphic<typename Type>::value
to determine whether Type
is a polymorphic type
(type-condition applies);
is_reference<typename Type>::value
to determine whether Type
is an (lvalue or rvalue)
reference;
is_rvalue_reference<typename Type>::value
to determine whether Type
is an rvalue
reference;
is_same<typename First, typename Second>::value
to determine whether types First
and Second
are
identical;
is_scalar<typename Type>::value
to determine whether Type
is a scalar type (in
contrast to an object type);
is_signed<typename Type>::value
to determine whether Type
is a signed type;
is_standard_layout<typename Type>::value
to determine whether Type
offers the
standard layout (type-condition applies);
is_trivial<typename Type>::value
to determine whether Type
is a trivial type
(type-condition applies);
is_trivially_assignable<typename Dest, typename Src>::value
to determine whether an object or value of
type Src
can trivially be assigned to an object of type Dest
(type-condition applies);
is_trivially_constructible<typename Type, typename ...Args>::value
to determine whether Type
is
trivially constructible from arguments in the Args
parameter pack
(type-condition applies to all types in Args
);
is_trivially_copy_assignable<typename Type>::value
to determine whether Type
supports
a trivial assignment operator (type-condition applies);
is_trivially_copy_constructible<typename Type>::value
to determine whether Type
is
trivially copy-constructible (type-condition applies);
is_trivially_copyable<typename Type>::value
to determine whether Type
is trivially
copyable (type-condition applies);
is_trivially_default_constructible<typename Type>::value
to determine whether Type
supports a trivial default constructor (type-condition applies);
is_trivially_default_destructible<typename Type>::value
to determine whether Type
supports a trivial default destructor (type-condition applies);
is_trivially_move_assignable<typename Type>::value
to determine whether Type
supports
a trivial assignment operator (type-condition applies);
is_trivially_move_constructible<typename Type>::value
to determine whether Type
is
trivially move-constructible (type-condition applies);
is_union<typename Type>::value
to determine whether Type
is a union type;
is_unsigned<typename Type>::value
to determine whether Type
is an unsigned type;
is_void<typename Type>::value
to determine whether Type
is void
;
is_volatile<typename Type>::value
to determine whether Type
is a volatile
qualified type;
make_signed<typename Type>::type
to construct a signed type;
make_unsigned<typename Type>::type
to construct an unsigned type;
remove_all_extents<typename Type>::type
if Type
is a (possibly multidimensional)
array of ElementType
values or objects then typedef type
equals ElementType
;
remove_const<typename Type>::type
to remove const
from Type
;
remove_cv<typename Type>::type
to remove const
and/or volatile
from Type
;
remove_extent<typename Type>::type
if Type
is an array of ElementType
values or
objects then typedef type
equals ElementType
. With
multi-dimensional arrays ElementType
is the type of the array from
which its first array dimension has been removed;
remove_pointer<typename Type>::type
to remove a pointer from Type
;
remove_reference<typename Type>::type
to remove a reference from Type
;
remove_volatile<typename Type>::type
to remove volatile
from Type
;
The actions in the first step might be made move aware by using
std::move
(e.g., to assign the source's values to a (possibly temporary)
destination). However, using std::move
can easily affect the source (e.g.,
when extending the source's memory, moving the existing data to its new
locations), which breaks the first step's assumption, as the target object is
now modified.
In this case (and generally) the move operation should not be allowed to throw exceptions. This, in turn, implies that it is difficult to write code which must offer a non-throwing moving constructor, if it uses (external) data types over which the moving constructor has no control. E.g.,
template <typename Type> class MyClass { Type d_f; public: MyClass() = default; MyClass(MyClass &&tmp) : d_f(move(tmp.d_f)) {} };Here,
MyClass
's author has no control over the design of Type
. If
Foreign
merely has a (possibly throwing) copy constructor, then the
following code breaks the no-throw assumption underlying move constructors:
MyClass<Foreign> s2(move(MyClass<Foreign>()));
If templates are able to detect whether Type
has non-throwing move
constructors then their implementations may be optimized by
calling these move constructors (already modifying their targets in the first
part of code offering the strong guarantee) in situations where otherwise the
non-modifying, but more expensive copy constructor has to be used.
The noexcept
keyword was introduced to allow such templates to perform
such optimizations. As with throw
lists, checking for noexcept
is
a run-time check, but the consequence of violating a noexept
declaration
are more serious than violating a throw
list: violating noexcept
results in calling std::terminate
, terminating the program, possibly
without unwinding the stack. In the context of the previous example, the
following code is flawlessly accepted by the compiler, demonstrating that
there is no compile-time checking of noexcept
:
class Foreign { public: Foreign() = default; Foreign(Foreign const &other) noexcept { throw 1; } };However, when this class's copy constructor is called, execution aborts with the following message:
terminate called after throwing an instance of 'int' Abort
Keep in mind that the current purpose of noexcept
is to allow templates to
optimize their code by using move operations where the code must also be able
to offer the string exception guarantee. Since noexcept
also offers the
conditional noexcept(condition)
syntax (with noexcept(true)
and
noexcept
having identical semantics), noexcept
can be made
conditional to the `noexcepting' nature of template types. Note that this is
not possible with throw
lists.
The following rules of thumb by be used to decide whether or
not to use noexcept
in your code:
noexcept
(this is identical to the advise
given for throw
lists);
noexcept(true)
if the
compiler can deduct that composing types also offer
noexcept(true)
, allowing template optimizations using move
operations where possible.
noexcept
declarations may still throw
exceptions (see the example given above). In the end noexcept
merely means that if such a function throws an exception
std::terminate
rather than std::unexpected
is called.
throw()
)
should now be provided with noexcept(true)
.
noexcept
specifications are required when using the following std
traits (declared in the <type_traits>
header file):
is_nothrow_constructible
is_nothrow_default_constructible
is_nothrow_move_constructible
is_nothrow_copy_constructible
is_nothrow_assignable
is_nothrow_move_assignable
is_nothrow_copy_assignable
is_nothrow_destructible
value
which is
true
if the class (and possibly its argument type list) matches
the characteristic after which the trait was named. E.g., if
MyClass(string const &) noexcept
is a constructor, then
std::is_nothrow_constructible<MyClass, string>::valueequals
true
. For the named members (like
is_nothrow_move_constructible
) parameter types do not have to be
specified, as they are implied. E.g.,
std::is_nothrow_move_constructible<MyClass>::valuereturns
true
if the move constructor has the noexcept
modifier.
transform
generic algorithm (cf. section 19.1.63):
template <typename Return, typename Argument> Return chop(Argument const &arg) { return Return(arg); }Furthermore assume that if
Return
is std::string
then the above
implementation should not be used. Instead, with std::string
a second
argument 1
should always be provided. If Argument
is a C++ string,
this would allow us to, e.g., return a copy of arg
from which its first
character has been chopped off.
Since chop
is a function, it is not possible to define a partial
specialization like this:
template <typename Argument> // This won't compile! std::string chop<std::string, Argument>(Argument const &arg) { return string(arg, 1); }Although a function template cannot be partially specialized it is possible to use overloading, defining a second, dummy,
string
parameter:
template <typename Argument> std::string chop(Argument const &arg, std::string) { return string(arg, 1); }Now it is possible to distinguish the two cases, but at the expense of a more complex function call. Moreover, in code this function may require the use of the
bind2nd
binder (cf. section 18.1.4) to
provide the dummy second argument, or it may require a (possibly expensive to
construct) dummy argument to allow the compiler to choose among the two
overloaded function templates.
Instead of providing a string
dummy argument the functions could
use the IntType
template (cf. section 23.2.1.1) to select the proper
overloaded version. E.g., IntType<0>
could be defined as the type of the
second argument of the first overloaded chop
function, and IntType<1>
could be used for the second overloaded function. From the point of view of
program efficiency this is an attractive option, as the provided IntType
objects are extremely lightweight. IntType
objects contain no data at
all. But there's also an obvious disadvantage as there is no intuitively clear
association between the int
value used and the intended type.
Instead of defining arbitrary IntType
types it is more attractive to
use another lightweight solution, using an automatic type-to-type
association. The struct TypeType
is a lightweight type wrapper, much like
IntType
. Here is its definition:
template <typename T> struct TypeType { typedef T Type; };
TypeType
is also a lightweight type as it doesn't have any data fields
either. TypeType
allows us to use a natural type association for
chop
's second argument. E.g, the overloaded functions can now be defined
as follows:
template <typename Return, typename Argument> Return chop(Argument const &arg, TypeType<Argument> ) { return Return(arg); } template <typename Argument> std::string chop(Argument const &arg, TypeType<std::string> ) { return std::string(arg, 1); }Using the above implementations any type can be specified for
Result
. If it happens to be a std::string
the appropriate overloaded
version is automatically selected. The following additional overload of the
function chop
capitalizes on this:
template <typename Result> Result chop(char const *txt) // char const * could also be a 2nd { // template type parameter return chop(std::string(txt), TypeType<Result>()); }Using the third
chop
function, the following statement produces the
text `ello world
':
cout << chop<string>("hello world") << '\n';Template functions do not support partial specializations. But they can be overloaded. By providing overloads with dummy type-arguments that depend on other parameters and calling these overloads from a overloaded function that does not require the dummy type argument a situation similar to partial specializations with class templates can often be realized.
struct
is a useful tool. It can be used as a type acting
analogously to the final 0-byte in NTB-strings.
It can simply be defined as:
struct NullType {};
T
be used as a `stand in' for another type
U
? Since C++ is a strongly typed language the answer is surprisingly
simple: T
s can be used instead of U
s if a T
is accepted as
argument in cases where U
s are requested.
This reasoning is behind the following class which can be used to determine
whether a type T
can be used where a type U
is expected. The
interesting part is that no code is actually generated or executed. All
decisions are made by the compiler.
In the second part of this section we'll show how the code developed in
the first part can be used to detect whether a class B
is a base class of
another class D
(the is_base_of
template (cf. section 23.6.2)
also provides an answer to this question). The code developed here closely
follows the example provided by Alexandrescu (2001,
p. 35).
First, a function test
is designed accepting a type U
.
The function test
returns a value
of the as yet unknown type Convertible
:
Convertible test(U const &);
The function test
is never implemented. It is only declared. If a type
T
can be used instead of a type U
then T
can also be passed as
argument to the above test
function.
On the other hand, if the alternate type T
cannot be used where a U
is
expected, then the compiler won't be able to use the above test
function. Instead, it uses an alternative function that has a lower
selection priority but that can always be used with any T
type.
C (and C++) offer a very general parameter list, a parameter list that is always considered acceptable. This parameter list is the familiar ellipsis which represents the worst case the compiler may encounter. If everything else fails, then the function defining an ellipsis as its parameter list is selected.
Usually that's not a productive alternative, but in the current situation it is exactly what is needed. When confronted with two candidate functions, one of which defines an ellipsis parameter, the compiler selects the function defining the ellipsis parameter only if the alternative(s) can't be used.
Following the above reasoning an alternative function test(...)
is
declared as well. This alternate function does not return a Convertible
value but a NotConvertible
value:
NotConvertible test(...);
If test
's argument is of type T
and if T
can be converted to U
then test
's return type is Convertible
. Otherwise NotConvertible
is returned.
This situation clearly shows similarities with the situation encountered in
section 23.6.1 where the value isClass
had to be determined
compile time. Here two related problems must be solved:
T
argument? This is more difficult than might
be expected at first sight as it might not be possible to define a T
. If
type T
does not define any constructor then no T
object can be
defined.
Convertible
be distinguished from NotConvertible
?
T
needs to be
defined. After all, the intent is to decide compile-time whether a type is
convertible and not to define a T
value or object. Defining objects is not
a compile-time but a run-time matter.
By simply declaring a function returning a T
we can
tell the compiler where it should assume a T
:
T makeT();This mysterious function has the magical power of enticing the compiler into thinking that a
T
object comes out of it. However, this function
needs a small modification before it will actually suit our needs. If, for
whatever reason, T
happens to be an array then the compiler will choke on
T makeT()
as functions cannot return arrays. This, however, is easily
solved, as functions can return references to arrays. So the above
declaration is changed into:
T const &makeT();
Next we pass a T const &
to test
:
following code:
test(makeT())Now that the compiler sees
test
being called with a T const &
argument it decides that its return value is Convertible
if a
conversion is in fact possible. Otherwise it decides that its return value
is NotConvertible
(as the compiler, in that case, selected test(...)
).
The second problem, distinguishing Convertible
from NotConvertible
is solved exactly the way isClass
could be determined in section
23.6.1, viz. by making their sizes different. Having done so the
following expression determines whether T
is convertible from U
or
not:
isConvertible = sizeof(test(makeT())) == sizeof(Convertible);By using
char
for Convertible
and Char2
(cf. section
23.6.1) for NotConvertible
the distinction can be made.
The above can be summarized in a class template LconvertibleToR
,
having two template type parameters:
template <typename T, typename U> class LconvertibleToR { struct Char2 { char array[2]; }; static T const &makeT(); static char test(U const &); static Char2 test(...); public: LconvertibleToR(LconvertibleToR const &other) = delete; enum { yes = sizeof(test(makeT())) == sizeof(char) }; enum { sameType = 0 }; }; template <typename T> class LconvertibleToR<T, T> { public: LconvertibleToR(LconvertibleToR const &other) = delete; enum { yes = 1 }; enum { sameType = 1 }; };
As the class template deletes its copy constructor no object can be
created. Only its enum
values can be interrogated. The next example writes
1 0 1 0
when run from a main
function:
cout << LconvertibleToR<ofstream, ostream>::yes << " " << LconvertibleToR<ostream, ofstream>::yes << " " << LconvertibleToR<int, double>::yes << " " << LconvertibleToR<int, string>::yes << "\n";
Base
is a (public) base class of a type
Derived
.
Inheritance is determined by inspecting convertibility of (const)
pointers. Derived const *
can be converted to Base const *
if
Base
is a public and unambiguous base class of Derived
;
Base
is void.
LBaseRDerived
. LBaseRDerived
provides
an enum yes
which is 1 if the left type is a base class of the right type
and both types are different:
template <typename Base, typename Derived> struct LBaseRDerived { LBaseRDerived(LBaseRDerived const &) = delete; enum { yes = LconvertibleToR<Derived const *, Base const *>::yes && not LconvertibleToR<Base const *, void const *>::sameType }; };
If code should not consider a class to be its own base class, then the
trait class LBaseRtrulyDerived
can be used to perform a strict test. This
trait class adds a test for type-equality:
template <typename Base, typename Derived> struct LBaseRtrulyDerived { LBaseRtrulyDerived(LBaseRtrulyDerived const &) = delete; enum { yes = LBaseRDerived<Base, Derived>::yes && not LconvertibleToR<Base const *, Derived const *>::sameType }; };
Example: the next statement displays 1: 0, 2: 1, 3: 0, 4: 1, 5: 0
when executed from a main
function:
cout << "\n" << "1: " << LBaseRDerived<ofstream, ostream>::yes << ", " << "2: " << LBaseRDerived<ostream, ofstream>::yes << ", " << "3: " << LBaseRDerived<void, ofstream>::yes << ", " << "4: " << LBaseRDerived<ostream, ostream>::yes << ", " << "5: " << LBaseRtrulyDerived<ostream, ostream>::yes << "\n";
This section itself was inspired by Andrei Alexandrescu's (2001) book Modern C++ design. It diverts from Alexandrescu's book in its use of variadic templates which were not yet available when he wrote his book. Even so, the algorithms used by Alexandrescu are still useful when using variadic templates.
C++ offers the tuple to store and retrieve
values of multiple types. Here the focus is merely on processing types. A
simple struct TypeList
is going to be used as our working horse for the
upcoming subsections. Here is its definition:
template <typename ...Types> struct TypeList { TypeList(TypeList const &) = delete; enum { size = sizeof ...(Types) }; };
A typelist allows us to store any number of types. Here is an example
storing the three types char, short, int
in a TypeList
:
TypeList<char, short, int>
sizeof
operator (cf. section 22.5) it is easy to obtain the number of types
that were specified with a certain TypeList
. For example, the following
statement displays the value 3:
std::cout << TypeList<int, char, bool>::size << '\n';
However, it's illustrative to see how the number of types specified with a
TypeList
could be determined if sizeof
hadn't been available.
To obtain the number of types that were specified with a TypeList
the following algorithm is used:
TypeList
contains no types, its size equals zero;
TypeList
contains types, its size equals 1 plus the number
of types that follow its first type.
TypeList
. In
executable C++ recursion could also be used in comparable situations. For
example recursion can be used to determine the length of an NTBS:
size_t c_length(char const *cp) { return *cp == 0 ? 0 : 1 + c_length(cp + 1); }While C++ functions usually use iteration rather than recursion, iteration is not available to template meta programming algorithms. In template meta programming repetition must be implemented using recursion. Furthermore, while C++ run-time code may use conditions to decide whether or not to start the next recursion template meta programming cannot do so. Template meta programming algorithms must resort to (partial) specializations. The specializations are used to select alternatives.
The number of types that are specified in a TypeList
can be computed
using the following alternate implementation of TypeList
, using a generic
struct
declaration and two specialization for the empty and non-empty
TypeList
(cf. the above description of the algorithm):
template <typename ...Types> struct TypeList; template <typename Head, typename ...Tail> struct TypeList { enum { size = 1 + TypeList<Tail...>::size }; }; template <> struct TypeList<> { enum { size = 0 }; };
TypeList
, an algorithm is used that either defines
`index' as -1 (if SearchType is not an element of the TypeList
) or it
defines `index' as the index of the first occurrence of SearchType in
the TypeList
. The following algorithm is used:
TypeList
is empty, `index' is -1;
TypeList
's first element equals SearchType, `index' is 0;
TypeList
's tail results in
`index' == -1;
TypeList
's tail) index is
set to 1 + the index obtained when searching for SearchType in the
TypeList
's tail.
ListSearch
expecting a parameter pack:
template <typename ...Types> struct ListSearch { ListSearch(ListSearch const &) = delete; };
Specializations handle the alternatives mentioned with the algorithm:
TypeList
is empty, `index' is -1:
template <typename SearchType> struct ListSearch<SearchType, TypeList<>> { ListSearch(ListSearch const &) = delete; enum { index = -1 }; };
TypeList
's head equals SearchType, `index'
is 0. Note that SearchType
is explicitly mentioned as the
TypeList
's first element:
template <typename SearchType, typename ...Tail> struct ListSearch<SearchType, TypeList<SearchType, Tail...>> { ListSearch(ListSearch const &) = delete; enum { index = 0 }; };
TypeList
's tail. The index
value returned by this search is stored in a tmp
enum value,
which is then used to determine index's value.
template <typename SearchType, typename Head, typename ...Tail> struct ListSearch<SearchType, TypeList<Head, Tail...> > { ListSearch(ListSearch const &) = delete; enum {tmp = ListSearch<SearchType, TypeList<Tail...>>::index}; enum {index = tmp == -1 ? -1 : 1 + tmp}; };
ListSearch
can be used:
std::cout << ListSearch<char, TypeList<int, char, bool>>::index << "\n" << ListSearch<float, TypeList<int, char, bool>>::index << "\n";
TypeList
is retrieving the type given its index. This inverse operation is
the topic of this section.
The algorithm is implemented using a struct TypeAt
. TypeAt
uses a
typedef
to define the type matching a given index. But the index might be
out of bounds. In that case we have several options:
Null
) that should not be used as a
type in the TypeList
. This type is going to be returned when the index is
out of bounds. Using this local type as one of the types in a TypeList
is
considered an error as its would conflict with the special meaning of Null
as the type returned at an invalid index.Null
from being returned by TypeAt
a static_assert
is used to catch the Null
type when it is encountered while evaluating
TypeAt
;
TypeAt
may define an enum value validIndex
set to
true
if the index was valid and set to false
if not.
TypeAt
works:
TypeAt
,
expecting an index and a TypeList
:
template <size_t index, typename Typelist> struct TypeAt;
static_assert
ends the compilation
template <size_t index> struct TypeAt<index, TypeList<>> { static_assert(index < 0, "TypeAt index out of bounds"); typedef TypeAt Type; };
Type
as the first type in
the TypeList
:
template <typename Head, typename ...Tail> struct TypeAt<0, TypeList<Head, Tail...>> { typedef Head Type; };
Type
is defined as Type
defined by TypeAt<index
- 1>
operating on the TypeList
's tail:
template <size_t index, typename Head, typename ...Tail> struct TypeAt<index, TypeList<Head, Tail...>> { typedef typename TypeAt<index - 1, TypeList<Tail...>>::Type Type; };
typeAt
can be used. Uncommenting the first variable
definition causes a TypeAt index out of bounds
compilation error:
typedef TypeList<int, char, bool> list3; // TypeAt<3, list3>::Type invalid; TypeAt<0, list3>::Type intVariable = 13; TypeAt<2, list3>::Type boolVariable = true; cout << "The size of the first type is " << sizeof(TypeAt<0, list3>::Type) << ", " "the size of the third type is " << sizeof(TypeAt<2, list3>::Type) << "\n"; if (typeid(TypeAt<1, list3>::Type) == typeid(char)) cout << "The typelist's 2nd type is char\n"; if (typeid(TypeAt<2, list3>::Type) != typeid(char)) cout << "The typelist's 3nd type is not char\n";
TypeList
is easy and doesn't require
recursive template meta programs. Two variadic template structs Append
and
Prefix
and two specializations are all it takes.
Here are the declarations of the two variadic template structs:
template <typename ...Types> struct Append; template <typename ...Types> struct Prefix;
To append or prefix a new type to a typelist, specializations expect a
typelist and a type to add. Then, they simply define a new TypeList
also
including the new type. The Append
specialization shows that a template
pack does not have to be used as the first argument when defining another
variadic template type:
template <typename NewType, typename ...Types> struct Append<TypeList<Types...>, NewType> { typedef TypeList<Types..., NewType> List; }; template <typename NewType, typename ...Types> struct Prefix<NewType, TypeList<Types...>> { typedef TypeList<NewType, Types...> List; };
TypeList
. Again, there are
several possibilities, each resulting in a different algorithm.
TypeList
;
TypeList
;
TypeList
.
TypeList
, keeping each type only once.
TypeList
. Which ones are eventually implemented depends of course on
the circumstances. As template meta programming is very powerful most if not
all algorithms can probably be implemented. As an illustration of how to erase
types from a TypeList
the above-mentioned algorithms are now developed in
the upcoming subsections.
EraseType
from a TypeList
a recursive algorithm is used once again. The template meta program uses a
generic Erase
struct and several specializations. The specializations
define a type List
containing the resulting TypeList
after the
erasure. Here is the algorithm:
Erase
expecting the type to erase and a TypeList
:
template <typename EraseType, typename TypeList> struct Erase;
TypeList
results:
template <typename EraseType> struct Erase<EraseType, TypeList<>> { typedef TypeList<> List; };
TypeList
's head matches the type to erase, then List
becomes a TypeList
containing the original TypeList
's tail
types:
template <typename EraseType, typename ...Tail> struct Erase<EraseType, TypeList<EraseType, Tail...>> { typedef TypeList<Tail...> List; };
TypeList
's tail. This results in a TypeList
to which the
orginal TypeList
's head must be prefixed. The TypeList
returned by the prefix operation is then returned as Erase::List
:
template <typename EraseType, typename Head, typename ...Tail> struct Erase<EraseType, TypeList<Head, Tail...>> { typedef typename Prefix<Head, typename Erase<EraseType, TypeList<Tail...>>::List >::List List; };
Erase
can be used:
cout << Erase<int, TypeList<char, double, int>>::List::size << '\n' << Erase<char, TypeList<int>>::List::size << '\n' << Erase<int, TypeList<int>>::List::size << '\n' << Erase<int, TypeList<>>::List::size << "\n";
TypeList
by its index we again use a
recursive template meta program. EraseIdx
expects a size_t
index value
and a TypeList
from which its idx
th (0-based) type must be
erased. EraseIdx
defines the type List
containing the resulting
TypeList
. Here is the algorithm:
EraseIdx
expecting the index of the type to erase and a TypeList
:
template <size_t idx, typename TypeList> struct EraseIdx;
TypeList
results:
template <size_t idx> struct EraseIdx<idx, TypeList<>> { typedef TypeList<> List; };
idx
becomes 0. At that point
the TypeList
's first type is ignored and List
is initialized
to a TypeList
containing the types in the orginal TypeList
's
tail:
template <typename EraseType, typename ...Tail> struct EraseIdx<0, TypeList<EraseType, Tail...>> { typedef TypeList<Tail...> List; };
EraseIdx
is applied to the TypeList
's
tail, providing it with a decremented value of idx
. To the
resulting TypeList
the orginal TypeList
's head is
prefixed. The TypeList
returned by the prefix operation is then
returned as EraseIdx::List
:
template <size_t idx, typename Head, typename ...Tail> struct EraseIdx<idx, TypeList<Head, Tail...>> { typedef typename Prefix< Head, typename EraseIdx<idx - 1, TypeList<Tail...>>::List >::List List; };
EraseIdx
can be used:
if ( typeid(TypeAt<2, EraseIdx<1, TypeList<int, char, size_t, double, int>>::List >::Type ) == typeid(double) ) cout << "the third type is now a double\n";
EraseType
from a TypeList
can easily be accomplished
by applying the erasure procedure not only to the head of the TypeList
but
also to the TypeList
's tail.
Here is the algorithm, described in a slightly different order than
Erase
's algorithm:
TypeList
is empty, there's nothing to erase, and an empty
TypeList
results. This is exactly what we do with Erase
, so we
can use inheritance to prevent us from having to duplicate elements of
a template meta program:
template <size_t idx> struct EraseIdx<idx, TypeList<>> { typedef TypeList<> List; };
EraseAll
expecting the type to erase and a TypeList
that is
derived from Erase
, thus already offering the empty TypeList
handling specialization:
template <typename EraseType, typename TypeList> struct EraseAll: public Erase<EraseType, TypeList> {};
TypeList
's head matches EraseType
EraseAll
is also
applied to the TypeList
's tail, thus removing all occurrences of
EraseType
from TypeList
:
template <typename EraseType, typename ...Tail> struct EraseAll<EraseType, TypeList<EraseType, Tail...>> { typedef typename EraseAll<EraseType, TypeList<Tail...>>::List List; };
TypeList
's head does not match
EraseType
) EraseAll
is applied to the TypeList
's tail.
The returned TypeList
consists of the original TypeList
's
initial type and the types of the TypeList
returned by the
recursive EraseAll
call:
template <typename EraseType, typename Head, typename ...Tail> struct EraseAll<EraseType, TypeList<Head, Tail...>> { typedef typename Prefix< Head, typename EraseAll<EraseType, TypeList<Tail...>>::List >::List List; };
EraseAll
can be used:
cout << "After erasing size_t from " "TypeList<char, int, size_t, double, size_t>\n" "it contains " << EraseAll<size_t, TypeList<char, int, size_t, double, size_t> >::List::size << " types\n";
TypeList
all the TypeList
's first
elements must be erased from the TypeList
's tail, applying the procedure
recursively to the TypeList
's tail. The algorithm, outlined below, merely
expects a TypeList
:
EraseDup
struct template is
declared. EraseDup
structures define a type List
representing the
TypeList
that they generate. EraseDup
calls expect a TypeList
as
their template type parameters:
template <typename TypeList> struct EraseDup;
TypeList
is empty it can be returned empty and we're done:
template <> struct EraseDup<TypeList<>> { typedef TypeList<> List; };
EraseDup
is first applied to the original TypeList
's
tail. By definition this results in a TypeList
from which all
duplicates have been removed;
TypeList
returned by the previous step might contain the
original TypeList
's initial type. If so, it is removed by applying
Erase
on the returned TypeList
, specifying the original TypeList
's
initial type as the type to remove;
TypeList
consists of the original TypeList
's
initial type to which the types of the TypeList
produced by the previous
step are appended.
template <typename Head, typename ...Tail> struct EraseDup<TypeList<Head, Tail...>> { typedef typename EraseDup<TypeList<Tail...>>::List UniqueTail; typedef typename Erase<Head, UniqueTail>::List NewTail; typedef typename Prefix<Head, NewTail>::List List; };
EraseDup
can be used:
cout << "After erasing duplicates from " "TypeList<double, char, int, size_t, int, double, size_t>\n" "it contains " << EraseDup< TypeList<double, char, int, size_t, int, double, size_t> >::List::size << " types\n";
But there's more to typelist than a mere intellectual challenge. In the final sections of this chapter the following topics are covered:
Multi
is now developed. The class template Multi
creates a new class from a
template template parameter Policy
defining the data storage policy and a
series of types from which Multi
is eventually derived. It does so by
passing its template parameters to its base class MultiBase
that in turn
creates a final class inheritance tree. Since we don't know how many types are
going to be used Multi
is defined as a variadic class template using a
template pack ...Types
.
In fact, the types that are specified with Multi
aren't that
interesting. They primarily serve to `seed' the class Policy
. Therefore,
rather than forwarding Multi
's types to MultiBase
they are passed to
Policy
and the sequence of Policy<Type>
types is then forwarded to
MultiBase
. Multi
's constructor expects initialization values for its
various Policy<Type>
s which are perfectly forwarded to MultiBase
.
The class Multi
(implementing its constructor in-class to save some
space) shows how a
template pack can be wrapped into a policy. Here is Multi
's definition:
template <template <typename> class Policy, typename ...Types> struct Multi: public MultiBase<0, Policy<Types>...> { typedef TypeList<Types...> PlainTypes; typedef MultiBase<0, Policy<Types>...> Base; enum { size = PlainTypes::size }; Multi(Policy<Types> &&...types) : MultiBase<0, Policy<Types>...>( std::forward<Policy<Types>>(types)...) {} };
Unfortunately, the design as described contains some flaws.
Policy
template template parameter is defined as
template <typename> class Policy
it can only accept policies expecting one
type argument. Contrary to this, std::vector
is a template expecting two
template arguments, the second one defining the allocation scheme used by
std::vector
. This allocation scheme is hardly ever changed, and most
applications merely define objects of types like vector<int>,
vector<string>
etc.. Template template parameters must, however, be specified
with the correct number and types of required template parameters so
vector
can't be specified as a policy for Multi
. This can be solved by
wrapping a more complex template in a simpler wrapper template, like so:
template <class Type> struct Vector: public std::vector<Type> { Vector(std::initializer_list<Type> iniValues) : std::vector<Type>(iniValues) {} };
Now Vector
provides std::vector
's second parameter using its
default template argument. Alternatively, a template using declaration
could be used.
TypeList
contains two types like int
and double
and the policy class is Vector
, then the MultiBase
class
eventually inherits from vector<int>
and vector<double>
. But if the
TypeList
contains identical types, like two int
type specifications
MultiBase
would inherit from two vector<int>
classes. Classes
cannot be derived from identical base classes as that would make it impossible
to distinguish among their members. Regarding this, Alexandrescu (2001)
writes (p.67):
There is one major source of annoyance...: you cannot use it when you have duplicate types in yourTypeList
.
.... There is no easy way to solve the ambiguity, [as the eventually derived class/FBB] ends up inheriting [the same base class/FBB] twice.
IntType
. The class template UWrap
has two template parameters: one
non-type parameter idx
and one type parameter. By ensuring that each
UWrap
definition uses a unique idx
value unique class types are
created. These unique class types are then used as base classes of the derived
class MultiBase
:
template <size_t nr, typename Type> struct UWrap: public Type { UWrap(Type const &type) : Type(type) {} };
Using UWrap
it's easy to distinguish, e.g., two vector<int>
classes: UWrap<0, vector<int>>
could refer to the first vector<int>
,
UWrap<1, vector<int>>
to the second vector.
Uniqueness of the various UWrap
types is assured by the class
template MultiBase
as discussed in the next section.
It must also be possible to initialize a Multi
class object. Its
constructor therefore expects the initialization values for all its Policy
values. So if a Multi
is defined for Vector, int, string
then its
constructor can receive the matching initialization values. E.g.,
Multi<Vector, int, string> mvis({1, 2, 3}, {"one", "two", "three"});
MultiBase
is Multi
's base class. It
defines a class that, eventually, is derived from the list of Policy
types that, in turn, were created by Multi
using any additional types that
were passed to it.
MultiBase
itself has no concept of a Policy
. To MultiBase
the
world appears to consist of a simple template pack whose types are used to
define a class from. In addition to the PolicyTypes
template pack,
MultiBase
also defines a size_t nr
non-type parameter that is used to
create unique UWrap
types. Here is MultiBase
's generic class
declaration:
template <size_t nr, typename ...PolicyTypes> struct MultiBase;
Two specializations handle all possible MultiBase
invocations. One
specialization is a recursive template. This template handles the first type
of MultiBase
's template parameter pack and recursively uses itself to
handle the remaining types. The second specialization is invoked once the
template parameter pack is exhausted and does nothing. Here is the definition
of the latter specialization:
template <size_t nr> struct MultiBase<nr> {};
The recursively defined specialization is the interesting one. It performs the following tasks:
UWrap
type. The uniqueness is
guaranteerd by using MultiBase
's nr
parameter when defining
UWrap
. In addition to nr
the UWrap
class receives the first type
of the template parameter pack made available to MultiBase
;
MultiBase
type is defined using as its first template argument an
incremented nr
value (thus ensuring the uniqueness of the UWrap
types
defined by recursive MultiWrap
types). Its second template argument is the
tail of the template parameter pack made available to MultiBase
MultiBase
class
hierarchy is provided in figure 27.
MultiBase
's constructor simply receives the initialization values that
were (originally) passed to the Multi
object. Perfect forwarding is used
to accomplish this. MultiBase
's constructor passes its first parameter
value to its UWrap
base class, also using perfect forwarding.
MultiBase
's recursive definition is:
template <size_t nr, typename PolicyT1, typename ...PolicyTypes> struct MultiBase<nr, PolicyT1, PolicyTypes...> : public UWrap<nr, PolicyT1>, public MultiBase<nr + 1, PolicyTypes...> { typedef PolicyT1 Type; typedef MultiBase<nr + 1, typename PolicyTypes...> Base; MultiBase(PolicyT1 && policyt1, PolicyTypes &&...policytypes) : UWrap<nr, PolicyT1>(std::forward<PolicyT1>(policyt1)), MultiBase<nr + 1, PolicyTypes...>( std::forward<PolicyTypes>(policytypes)...) {} };
Multi
class template defines PlainTypes
as the TypeList
holding all the types of its parameter pack. Each MultiBase
derived from a
UWrap
type also defines a type Type
representing the policy type that
was used to define the UWrap
type and a type Base
representing the
type of its nested MultiBase
class.
These three type definitions allow us to access the types from which the
Multi
object was created as well as the values of those types.
The class template typeAt
, is a pure template meta program class template
(it has no run-time executable code). It expects a size_t idx
template
argument specifying the index of the policy type in a Multi
type object as
well as a Multi
class type. It defines the type Type
as the Type
defined by Multi
's MultiBase<idx, ...>
base class. Example:
typeAt<0, Multi<Vector, int, double>>::Type // Type is vector<int>
The class template typeAt
defines (and uses) a nested class template
PolType
doing all the work. PolType
's generic definition specifies two
template parameters: an index used to specify the index of the requested type
and a typename initialized by a MultiBase
type argument. PolType
's
recursive definition recursively reduces its index non-type parameter,
passing the next base class in MultiBase
's inheritance tree to the
recursive call. As PolType
eventually defines the type Type
to be the
requested policy type the recursive definition defines its Type
as the
type defined by the recursive call. The final (non-recursive) specialization
defines the initial policy type of the MultiBase
type as Type
. Here is
typeAt
's definition:
template <size_t index, typename Multi> class typeAt { template <size_t idx, typename MultiBase> struct PolType; template <size_t idx, size_t nr, typename PolicyT1, typename ...PolicyTypes> struct PolType<idx, MultiBase<nr, PolicyT1, PolicyTypes...>> { typedef typename PolType< idx - 1, MultiBase<nr + 1, PolicyTypes...>>::Type Type; }; template <size_t nr, typename PolicyT1, typename ...PolicyTypes> struct PolType<0, MultiBase<nr, PolicyT1, PolicyTypes...>> { typedef PolicyT1 Type; }; public: typeAt(typeAt const &) = delete; typedef typename PolType<index, typename Multi::Base>::Type Type; };
The types specified by Multi
's parameter pack can also be retrieved using
a second helper class template: plainTypeAt
. Example:
plainTypeAt<0, Multi<Vector, int, double>>::Type // Type is intThe class template
plainTypeAt
uses a comparable (but simpler)
implementation than typeAt
. It is also a pure template meta program class
template defining a nested class template At
. At
is implemented like
typeAt
but it visits the types of the original template pack that was
passed to Multi
, and made available by Multi
as its PlainTypes
type. Here is plainTypeAt
's definition:
template <size_t index, typename Multi> class plainTypeAt { template <size_t idx, typename List> struct At; template <size_t idx, typename Head, typename ...Tail> struct At<idx, TypeList<Head, Tail...>> { typedef typename At<idx - 1, TypeList<Tail...>>::Type Type; }; template <typename Head, typename ...Tail> struct At<0, TypeList<Head, Tail...>> { typedef Head Type; }; public: plainTypeAt(plainTypeAt const &) = delete; typedef typename At<index, typename Multi::PlainTypes>::Type Type; };
Arguably the neatest support template is get
. This is a function template
defining size_t idx
as its first template parameter and typename Multi
as its second template parameter. The function template get
defines one
function parameter: a reference to a Multi
, so it can deduct Multi
's
type by itself. Knowing that it's a Multi
, we reason that it is also a
UWrap<nr, PolicyType>
and therefore also a PolicyType
, as the latter
class is defined as a base class of UWrap
.
Since class type objects can initialize references to their base classes the
PolicyType &
can be initialized by an appropriate UWrap
reference,
which in turn can be initialized by a Multi
object. Since we can
determine PolicyType
using TypeAt
(note that evaluating typename
typeAt<idx, Multi>::Type
is a purely compile-time matter), the get
function can very well be implemented inline by a single return
statement:
template <size_t idx, typename Multi> inline typename typeAt<idx, Multi>::Type &get(Multi &multi) { return static_cast< UWrap<idx, typename typeAt<idx, Multi>::Type> &>(multi); }
The intermediate UWrap
cast is required to disambiguate between
identical policy types (like two vector<int>
types). As UWrap
is
uniquely determined by its nr
template argument and this is the number
argument that is passed to get
ambiguities can easily be prevented.
Multi
and its support templates have been developed, how can a
Multi
be used?
A word of warning is in place. To reduce the size of the developed classes
they were designed in a minimalist way. For example, the get
function
template cannot be used with Multi const
objects and there is no default,
or move constructor available for Multi
types. Multi
was designed to
illustrate some of the possibilities of template meta programming and
hopefully Multi
's implementation served that purpose well. But can it be
used? If so, how?
This section provides some annotated examples. They may be concatenated to
define a series of statements that could be placed in a main
function's
body, which would result in a working program.
Policy
could be defined:
template <typename Type> struct Policy { Type d_type; Policy(Type &&type) : d_type(std::forward<Type>(type)) {} };
Policy
defines a data member and it can be used to define Multi
objects:
Multi<Policy, string> ms(Policy<string>("hello")); Multi<Policy, string, string> ms2s(Policy<string>("hello"), Policy<string>("world")); typedef Multi<Policy, string, int> MPSI; MPSI mpsi(string("hello"), 4);
Multi
class or object
either use the ::size
enum value (using the Multi
class) or the
.size
member (using the Multi
object):
cout << "There are " << MPSI::size << " types in MPSI\n" "There are " << mpsi.size << " types in mpsi\n";
plainTypeAt
:
plainTypeAt<0, MPSI>::Type sx = "String type"; plainTypeAt<1, MPSI>::Type ix = 12;
cout << static_cast<Policy<string> &>(mpsi).d_type << '\n' << static_cast<Policy<int> &>(mpsi).d_type << '\n';
Policy<Type>
types. In that case get
still works fine:
typedef Multi<Policy, int, int> MPII; MPII mpii(4, 18); cout << get<0>(mpii).d_type << ' ' << get<1>(mpii).d_type << '\n';
std::vector
in a Vector
:
typedef Multi<Vector, int, double> MVID; MVID mi({1, 2, 3}, {1.2, 3.4, 5.6, 7.8});
Multi
type:
typeAt<0, Multi<Vector, int>>::Type vi = {1, 2, 3};
Vector
is a std::vector
, the reference
returned by get
support index operators that can be used as left hand side
or right hand side operands:
cout << get<0>(mi)[2] << '\n'; get<1>(mi)[3] = get<0>(mi)[0]; cout << get<1>(mi)[3] << '\n';
Assume we are processing std::vector
objects. Vectors may be assigned to
each other, but that's about it. We've seen (cf. section 12.4.2) that its
member functions tend to operate on the current vector, but arithmetic
operations like addition, subtraction, multiplication and the like cannot
be applied to pairs of vectors.
Furtunately implementing, e.g., the addition operator for vectors is not
particularly difficult. If VecType
is our vector type, then implementing
free functions like
VecType operator+(VecType const &lhs, VecType const &rhs)
and
VecType operator+(VecType &&lhs, VecType const &rhs)
performing the additions is a simple exercise (cf. chapter
11).
Now consider an expression like one + two + three + four
. It takes four
steps to compute this sum: first, tmp = one
is computed, creating the
eventual return value. The vector tmp
is an (in practice anonymous)
temporary variable. Then tmp += two
is computed, followed by tmp +=
three
, and finally by tmp += four
, obtaining the final result (of course
we shouldn't implement std::vector::operator+=
as the std namespace is
off-limits to us, and we shouldn't derive a class from std::vector
offering operator+=
according to Liskov's Substitution Principle
(cf. section 14.7), but we could get around that,
and here we simply assume operator+=
is available).
Here's how we might implement operator+=
for VecType
:
VecType &VecType::operator+=(VecType const &rhs) { for (size_t idx = 0, end = size(); idx != end; ++idx) (*this)[idx] += rhs[idx]; return *this; }Consider this implementation: once we add a
VecType
object and such
objects have n
elements then we have to perform 2 * n
index
evaluations. When adding k VecType
objects this sums up to about 2 * k
* n
index expression evaluations: a lot of evaluations if we're adding many
and/or big vectors.
If instead we could manage to perform the evaluations `row by row', each
vector element would be accessed only once. This would dramatically cut down
on our index evaluations. We would only need to perform approx. n * k
index expression evaluations.
Expression templates allow us to achieve precisely this kind of optimization. We'll have a look at their design and implementation in the coming sections.
one + two + three + four
, where the objects are vectors having n
elements, then if we have k
vectors we have to perform a total of k * 2
* n
index evaluations.
Expression templates allow us to avoid many of these evaluations. When using expression templates these templates may access the vectors, but their elements are not accessed during addition operations.
Assuming our expression template is named ET, and we want to add one + two
+ three
, then the first +
operator merely creates ET(one, two)
. Note
that no addition is actually performed, ET
merely stores (constant)
references to one
(becoming ET's lhs
data member) and two
(becoming ET's rhs
data member). In general, ET
stores references to
the two arguments that are passed to its constructor.
At the next addition operator another ET
is created. Its constructor
arguments are, respectively, the ET
object that has just been constructed
for one
and two
, and the vector three
. Again, no addition is
performed by the ET objects.
This algorithm easily generalizes to any number of vectors. Parentheses can
also be used. E.g., (one + two) + (three + four)
results in
ET(ET(one, two), ET(three, four))
Presumably, at some point we want to obtain the sum of the vectors. For this
the expression template is provided with a conversion operator, converting the
ET
object to a vector, or maybe an assignment operator doing the same.
The conversion operator looks like this:
operator ET::VecType() const { VecType retVal; retVal.reserve(size()); for (size_t ix = 0, end = size(); ix != end; ++ix) new(&retVal[ix]) value_type((*this)[ix]); return retVal; }Placement new is used for efficiency reasons: there's no need to initialize
retVal
with default values first. The really interesting part,
however, is hidden behind the (*this)[idx]
expression: at this point the
real addition takes place.
ET's
index operator simply adds the values returned by the
corresponding index expressions of its lhs
and rhs
data members. If a
data member refers to a vector then the corresponding vector element is used,
adding it to the other data member's value. If a data member itself refers to
an ET object, then that nested ET
object's index operator performs the
same addition on its own data members, returning their sum. So, an expression
like (*this)[0]
returns first[0] + second[0] + third[0]
, and the
computed sum is then stored in retVal[0]
using placement new.
In this case the required number of index expression evaluations are n
* k
(for the n elements of the k vectors) plus n (for the n elements of
retVal
, adding up to (k + 1) * n
).
Since (k + 1) * n < 2 * k * n
for k > 1
expression templates evaluate
the requested addition more efficiently than the traditional implementation of
operator+
. An additional benefit of using expression templates is that
they do not create additional temporary vector objects when parenthesized
expressions are used.
typedef std::vector<int> IntVect
to illustrate
the construction of an expression template.
Starting point is a simple main
function, in which several IntVect
objects are added. E.g.,
int main() { IntVect one; IntVect two; IntVect three; IntVect four; // ... assume the IntVects somehow receive values four = one + two + three + four; }At this point the code does not suggest that expression templates are going to be used. However,
operator+'s
implementation is special: it's a
template merely returning an object constructed by operator+
:
template<typename LHS, typename RHS> BinExpr<LHS, RHS, plus> operator+(LHS const &lhs, RHS const &rhs) { return BinExpr<LHS, RHS, plus>(lhs, rhs); }
Our expression template is called BinExpr
. It has three template type
parameters: two object types and a template template parameter performing the
requested operation. Its declaration looks like this:
template<typename LHS, typename RHS, template<typename> class Operation> struct BinExpr;Since
LHS
and RHS
can either be the data type that is processed by
the expression template, or a BinExpr
two different typenames are
required. Operation
is the operation that is performed by the expression
template. By using a template template parameter we can use BinExpr
to
perform any operation we want, not just addition. Predefined function
templates like std::plus
can be used for the standard arithmetic
operators; for other operators we can define our own function templates.
BinExpr's
constructor initializes constant references to lhs
and
rhs
. Its in-class implementation is
BinExpr(LHS const &lhs, RHS const &rhs) : d_lhs(lhs), d_rhs(rhs) {}
To retrieve the resulting IntVect
a conversion operator is defined. We
already encountered its implentation (in the previous section). Here is it,
as an in-class implemented BinExpr
member:
operator ObjType() const { ObjType retVal; retVal.reserve(size()); for (size_t idx = 0, end = size(); idx != end; ++idx) new(&retVal[idx]) value_type((*this)[idx]); return retVal; }We return to the type
ObjType
below. At this point it can be
considered an IntVect
. The member size()
simply returns
d_lhs.size()
: in any sequence of IntVect
additions LHS
eventually
is an IntVect
, and so every BinExpr
defines a valid size()
like
so:
size_t size() const { return d_lhs.size(); }
The only remaining member to implement is operator[]
. Since it
receives an index, it only needs to perform the requested operation on the
corresponding index elements of its d_lhs
and d_rhs
data members. The
beauty of expression templates is that if either one itself is a BinExpr
that expression template in turn calls its operator[]
, eventually
performing the requested operation on all corresponding elements of all
IntVect
objects. Here is its implementation:
value_type operator[](size_t ix) const { static Operation<value_type> operation; return operation(d_lhs[ix], d_rhs[ix]); }This implementation uses another type:
value_type
which is the
type of the elements of the vector type that is processed by the expression
template. Like ObjType
before, its definition is covered below. The static
data member operation
simply is an instantiation of the Operation
type
that is specified when constructing an ExprType
object.
So, it's about time to have a look at ObjType
and value_type
. We do
that in the next section.
BinExpr
expression template needs to be aware of two types before it
can instantiate objects. First, ObjType
must be known, as this is the
type of object that is handled by the expression template. ObjType
objects
contain values, and we require that the type of these values can be determined
as ObjType::value_type
. E.g., for our IntVect
data type value_type
is int
.
In expressions like one + two + three
, the BinExpr
expression template
receives two IntVect
objects. This is always true: the BinExpr
that is
first constructed receives two IntVect
objects. In this case ObjType
is simply LHS
, and ObjType::value_type
is also available: either
value_type
is already defined by LHS
or BinExpr
requires that
it defines type value_type
.
Since arguments to BinExpr
objects are not always of the basic
ObjType
type (BinExpr
objects at the next nesting level receive at
least one BinExpr
argument) we need a way to determine ObjType
from a
BinExpr
. For this we use a trait class. The
trait class BasicType
receives a typename template argument, and equates
its type ObjType
to the received template type argument:
template<typename Type> struct BasicType { typedef Type ObjType; };A specialization handles the cae where
Type
in fact is a BinExpr
:
template<typename LHS, typename RHS, template<typename> class Operation>
template<typename LHS, typename RHS, template<typename> class Operation> struct BasicType<BinExpr<LHS, RHS, Operation>> { typedef typename BinExpr<LHS, RHS, Operation>::ObjType ObjType; };
Since BinExpr
requires that ObjType::value_type
is a defined
type, value_type
has automatically been taken care of.
As BinExpr
refers to BasicType
and BasicType
refers to
BinExpr
somewhere we must provide a forward declaration. As BinExpr's
declaration has already been provided, we start with that declaration,
resulting in:
BinExpr's declaration BasicType's definition BasicType's specialization (for BinExpr) template<typename LHS, typename RHS, template<typename> class Operation> class BinExpr { LHS const &d_lhs; RHS const &d_rhs; public: typedef typename BasicType<RHS>::DataType DataType; typedef typename DataType::value_type value_type; // all BinExpr member functions };